Yes. most of it. But at the end all that energy ends up as 'thermal energy' of the water.
Before addressing the particular question let's first take a look at the 'big picture'
of the situation of an object falling into water.
Suppose an object originally rests at a given altitude over the water surface of a
swimming pool. Then it's allowed to free drop to the pool and gets to rest in the
bottom of the pool. (For simplicity's sake, object and pool's water are originally at
the same temperature and air drag on the object as it falls to the water's surface is
negligible).
What is going to happen at the end, is that the object's original potential energy,
measured from the bottom of the pool to the starting altitude, ends up in the pool's
water as thermal energy. Since we would most likely think of the experiment done
with an object not to big with respect to the pool like a Bowling ball, and a
dropping height measured from the pools floor of just a few meters, the energy that the water will gain at the end once the water has recovered its original
tranquility, will be too small to be sensed by a household temperature.
Now let's address the question 'in question', the description of the energy changes.
1.- When the object free falls from its resting point to the water's surface, the
kinetic energy developed comes from the potential energy lost at that point.
2.- The object has a 'collision' with the water's surface and suffers a sharp drop of
of its kinetic energy. A 'collision' of two objects makes the particles that conform
the objects (atoms, molecules) vibrate (part of this vibrations are transferred to the
surrounding medium, e.g., air, as sound). Vibration of the atoms or molecules of a
body are part of its 'thermal energy'. So, a rather small part of the kinetic energy
lost in the collision is transformed to thermal energy of the object and the water
involved in the collision. Most of the object's kinetic energy is invested in
displacing the water giving it motion (kinetic energy), local turbulence is developed
and the 'outward ripples' (waves) on the water surface are consequence of this
action.
3.- The object will continue making its way to the bottom losing its remaining
potential energy, giving motion to the water surrounding it, and although in very
small amount, some of it is invested in friction that ends as thermal energy in the
surroundings (the water).
4.- In conclusion, all the mechanical energy that the object gives to the water in
this hypothetical experiment in a pool ends up in the pool's water thermal energy.
false
652 cm³
The bouyant force on an object is equal to the weight of the fluid the object displaces.
by measuring the amount of water it displaces
No, it sinks
To find the volume of an irregular object such as a rock, you have to use displacement. If you place the object in a graduated cylinder filled with water, the volume of the object is equal to the amount of water that the object displaces. For example, if a graduated cylinder is filled with 100mL of water, and you place an object such as a rock and the water rises from 100mL to 106mL, then the volume of the rock is 6.
false
volume of water an object displaces is equal to the volume of the part of the object inside it
No relationship at all. But there is a definite and direct relationship between theamount of water than an object displaces and the object's volume.
Two answers to this: 1. If the object floats on the fluid, then it displaces its own mass in fluid. 2. If the object sinks, it will displace its own volume in fluid.
652 cm³
a submerged object displaces liquid which is equal to its volume
Archimedes' principles: -- An object in a fluid experiences an upward force equal to the weight of the displaced fluid. -- A sinking object displaces its volume. -- A floating object displaces its weight.
The bouyant force on an object is equal to the weight of the fluid the object displaces.
etrw
Applied force.
652 cc (unless it was floating).
The amount of liquid a object displaces is directly proportional to the density of the object