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Simple distance-speed-time problem. We know that s = d/t, or speed is distance over time.

We know that the earth has an orbit around the sun of around 93,000,000 (93 million) miles. Call this r, the radius of the earth's orbit.

This means that the distance the earth travels once around the sun is (using the circumference of a circle formula C = 2*Pi*r) is

d = 2*Pi*r = 2*Pi*93,000,000 = 584,336,200 miles (to the nearest hundred.)

The time it takes to orbit the earth is one year, which is 365.25 days long. This works out to 8,766 hours. So if we are working in miles per hour, we get:

s = 584,336,000/8,766 = 66,700 miles per hour, with a bit of rounding. In kilometres per hour this would work out as around 106,700 kph.

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15y ago

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