Relationship of wavelength and frequency is inversely proportional the shorter the wavelength the higher the frequency?

Answer 1

distance between two successive crests or troughs is called one wavelength and at any point the number of succesive crests or troughs passing through a given point in one second is called its frequency

Wave speed c = frequency f times wavelength lambda

For a wave in air the speed of sound is c = 343 meters per second at 20 degrees Celsius.

For a wave in vacuum the speed of light is c = 299 792 458 meters per second.

frequency f = wave speed c divided by wavelength lambda.

There is a useful calculator for converting wavelength to frequency and vice versa.

Scroll down to related links and look at "Acoustic waves or sound waves in air".

Answer 2

Yes, this is true as long as the wave velocity is constant. The relationship between wavelength, L , velocity, v , and frequency, f , is; L = v/f . So if L gets smaller then either v must get smaller or f gets larger (or both). As an example where f does not change, consider a sound wave traveling thru a metal bar. It comes to the end of the bar and enters the air. Sound travels faster in metal then air so now you have this situation; A person counting the waves go by in the metal, just before it enters the air ,lets say counts one every second. Now a person counting the waves go by just after it enters the air will count fewer then one per second because the wave speed is slower. This means more waves enter the "metal/air" surface then leave it. This is not very reasonable and is not what happens. What happens is the wavelength in air becomes shorter so the person still counts one per second (which is the frequency). So that's a case of shorter wavelength, constant frequency, & smaller wave velocity.