Frequency.
Speed of sound c is frequncy f times wavelength lambda. c = f times lambda Scroll down to related links and look at "Conversion: frequency f to wavelength lambda and wavelength to frequency".
You can see how the frequency of a wave changes as its wavelength changes by using the formula Velocity= wavelength x frequencyIf for example we are talking about the speed of light (Which does change) and the wavelength is reduced, then the frequency has to increase in order to balance out to the speed of light.Another way to view it is like this:The frequency of a wave changes with the wavelength by what happens to the wavelength. For instance, if the wavelength is doubled, the frequency is halved, and vise versa.
Lambda = wavelength = 1.0 Angstrom = 1.0 x 10-10 mf = frequencyc = speed of light (2.9979 x 108 m/s)*Use the following equation:c = lambda x f (lambda times f)*Rearrange the equation for frequency:f = c / (lambda) (c divided by lambda)= (2.99798 m/s) / (1.0 x 10-10 m/s)= [answer]
Consider a string tied toward one side and you are moving the flip side in your grasp. On the off chance that you painstakingly watch, the wave is flying out through the rope to the tied end. In any case, the particles, which constitute the rope move just in here and there bearing. They don't move parallel to the rope by any stretch of the imagination. In the event that that was the situation, after a touch of time, you would have had a rope that was denser on the tied end. So molecule speed is opposite to the wave speed in a transverse wave. It is equivalent to (omega) squared times the wave speed.
If you take a snapshot of a physical wave (such as an ocean wave) using a camera for example, you can then measure the distance from one peak to the next. The spacing is the wavelength. See the "mathematical description" section of the related link. When an an electromagnetic wave is discussed, the wavelength is equal to the quotient (speed of light / frequency). The formula applies to other waves too, just that the speed of light being replaced with the speed of the specific wave in question. For a traveling wave, see the "simple harmonic motion" illustration in the link -- the peak of the wave is moving at a finite speed to the right (i.e. wave speed). The wave frequency is how many times, at any spot in space (the center line, or the two boundaries of the "simple harmonic motion" illustration can be selected to do the counting), the wave peaks, troughs, and then peak again. Visible lights, X-rays, microwave, and gamma rays, all have a range of frequencies published in the literature. =====================
wavelength
Divide the speed by the wavelength. (For any wave, the wavelength times the frequency is equal to the speed of the wave.)
The product of (wavelength) times (frequency) is equal to the speed of the wave.
(wavelength) x (frequency) = wave speed
Since the speed of the wave is equal to the wavelength times the frequency, all you need to do is divide the speed by the wavelength in this case.
Convert the cm to meters, to have compatible units. Then use the fact that the frequency times the wavelength is equal to the speed of the wave. In this case, you can divide the speed by the wavelength, to get the frequency.
The speed or velocity of a wave is equal to the wavelength times the frequency. The period (amount of time for one wavelength to occur) is equal to 1 over the frequency (the inverse of its frequency).
frequency for apex learners not speed :)
Wavelength = (speed) divided by (frequency) Frequency = (speed) divided by (wavelength) Speed = (frequency) times (wavelength)
Speed = (frequency) times (wavelength) Frequency = (speed) divided by (wavelength) Wavelength = (speed) divided by (frequency)
The product of (wavelength) times (frequency) is the speed.
The wavelength of waves travelling with the same speed would decrease if the frequency of the waves increases. This is because, speed of a wave is the product of the distance of the wavelength times the frequency of the wave. The velocity of a wave is usually constant in a given medium.