Well, well, well, look who's trying to get all scientific on us! The decomposition of CuSO4 involves heating it to break it down into copper oxide (CuO) and sulfur trioxide (SO3). So, if you're feeling like a chemist today, go ahead and whip up some CuSO4 and watch the magic happen. Just don't forget your safety goggles, honey!
159.6086g
Methane gas is released, as well as carbon dioxide, during decomposition.
Synthesis and decomposition reactions are opposites. Synthesis: A + B -> C Decomposition: C -> A + B They both involve three elements or compounds, one of which is a combination of the other two. An example: N2O5 -> NO2 + NO3 Is a decomposition reaction.
a chemical decomposition reaction produced by passing an electric current through a solution containing ions is known as electrolytic decomposition reaction
yes alabaster was used to prevent decomposition or roting
CuSO4•5H2O + heat ---> CuSO4 + 5H2O
This is not a decomposition reaction.
CuSO4.5H2O(s) --> CuSO4(s) + 5H2O(g)
CuCO3 --> CO2 + CuO (gas + black powder) Further heating may result in : CuO --> 2Cu + O2 (metal copper + gas)
Initial chemical formula is: CuSO4.5H2O. Dehydration: - CuSO4.3H2O at 63 0C - CuSO4.H2O at 109 0C - CuSO4 at 200 0C Thermal decomposition after 650 0C: CuSO4 = CuO + SO3
The balanced chemical equation for the decomposition of copper (II) sulfate pentahydrate ((CuSO_4 \cdot 5H_2O)) is: [CuSO_4 \cdot 5H_2O \rightarrow CuSO_4 + 5H_2O] This equation represents the decomposition of copper (II) sulfate pentahydrate into copper (II) sulfate and water. The balanced equation shows that one mole of copper (II) sulfate pentahydrate decomposes into one mole of copper (II) sulfate and five moles of water.
The word equation for the thermal decomposition of copper sulfate is: Copper(II) sulfate (CuSO4) on heating breaks down into copper(II) oxide (CuO) and sulfur trioxide gas (SO3).
CuSO4 * 5H2O ----> CuSO4 + 5H2O. This is true because CuSO4 * 5 H2O is a salt weakly bounded to water, that is why it is hydrous. When it decomposes, the weak bonds are broken making the products above. CuSO4*5H2O formula is [Cu(OH2)4]SO4*H2O CuSO4 + 5H2O --> [Cu(OH2)4]SO4*H2O
CuSO4 is copper (II) sulfate. The balanced equation for CuSO4 with water is CuSO4 + H2O reacts to become Cu+2 + HSO4-2 + OH-.
Yes. They do not contain the same proportion of CuSO4, however. The moles of CuSO4 . 5 H2O are more massive.
Yes, CuSO4 is an electrolyte.
When copper sulfate pentahydrate is heated, the water molecules are driven off, leaving anhydrous copper sulfate as the solid residue. The chemical equation for this reaction is: CuSO4*5H2O(s) → CuSO4(s) + 5H2O(g).