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The use of pythagoras theorem helps out here. Make it a right angled triangle.

x2 = 152 + 102. X2 is 225 + 100 = 325. Square root of 325 is 18.03 metres

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What is the the length of the diagonal of a 10 cm by 15 cm rectangle?

Use Pythagoras: diagonal² = length² + width² → diagonal² = (10 cm)² + (15 cm)² → diagonal = √(10² + 15²) cm = √325 cm = 5 √13 cm ≈ 18 cm


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What is the length of the diagonal of a 10 centimeters by 15 centimeters rectangle?

To find the length of the diagonal of a rectangle, you can use the Pythagorean theorem. For a rectangle with lengths of 10 cm and 15 cm, the diagonal (d) can be calculated as (d = \sqrt{10^2 + 15^2}). This simplifies to (d = \sqrt{100 + 225} = \sqrt{325}), which is approximately 18.03 cm. Thus, the length of the diagonal is about 18.03 centimeters.


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A carpenter is framing a wall that is 8 feet high and 15 feet long. If the carpenter wants to be sure that the sides of the wall meet at right angles then what should the diagonal measurement of the w?

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