Earth bulge describes the effect of physical earth curvature along a direct path between two points on the earth's surface. The earth surface appears to "bulge upwards" in the path, with the peak of the bulge occurring at mid-path. This assumes that the earth's surface is flat, with no topological variation along the path between the two points. In radio path profiling, the effects of physical "earth bulge" must be added to the terrain topology (earth surface variation) profile. The amount of physical "earth bulge" along a path can be calculated from the following formula: h= 1.5 d1• d2 Where: h = Vertical distance from a horizontal reference line in feet d1 = Distance from the data point to point A in miles d2 = Distance from the data point to point B in miles
A bulge is a chunk of information that has little relationship to the writer's topic
The diameter of the earth at the equator is 12,756.32 kilometers or 7,926.41 miles. The diameter of the earth through the poles is 12,715.43 kilometers or 7,901.00 miles. Thus the earth is 41 km or 25 miles wider than it is tall, giving it a slight bulge at the equator. This shape is known as an ellipsoid or more properly, geoid (earth-like).
no, you cannot calculate effort for effort is not an equation its is just how much force you apply on an object their is no way to show the formula for effort their is no formula for effort no you're wrong you don't even know which there you are suppose to use so how do you know the answer you probally guest.
well density measures how much an object is by its size and you calculate it by finding the mass then volume.Then you divide the two answers then whatever answer you get,you round it to the nearest tenths
No. Even if everybody were to run in the same direction around the earth they would effect the rate of rotation only very very slightly. You have to calculate the total angular momentum produced by the running population and subtract (or add depending on the direction that they run) the total angular momentum on the earth, (first calculate the moment of inertia of a solid iron sphere the size of the earth then multiply by the angular velocity (circumference of the earth over a 24 hour period)). I'm sure you will find that the value for the earth wins out by a considerable margin. It would be an interesting calculation to make however. Population of the earth times the average mass of a person, times the medial running speed times the radius of the earth. I'll let someone else do that.
To calculate the circumference of the Earth, you can use the formula C 2r, where C is the circumference, is a constant (approximately 3.14159), and r is the radius of the Earth. The average radius of the Earth is about 6,371 kilometers. Plug this value into the formula to find the circumference.
Earth's equatorial bulge is primarily caused by its rotation. As the Earth spins on its axis, the centrifugal force generated by this rotation causes the equatorial region to bulge outwards. This results in the Earth being slightly flattened at the poles and oblate spheroid in shape.
The Earth is not a perfect sphere. The rotation of the planet has caused the Earth to 'bulge' to a certain extent. The distance around the Equator is further than any other measurement of the circumference.
The equatorial bulge is caused by the Earth's rotation. As the Earth spins on its axis, the centrifugal force generated by this rotation causes the planet to bulge at the equator. This bulge results in the Earth being slightly wider at the equator than it is at the poles.
Answer,The surface area of earth is 510072000 Sq.km.And the formula of earth is,the earth is sphere.: The area of earth = Area of sphere" " = 4*pi*r2= 4*22/7*4057390.9= 510072000
At the equator. The spin of the earth is fastest there.
A major effect of the Moon's revolution around the Earth is the tides. The gravity of the Moon (and of the Sun, too) pull on the Earth's oceans.The oceans bulge outward on the side facing the Moon and the opposite side of the Earth - shorelines underneath the bulge experience high tide. This bulge is called the tidal bulge. The Earth rotates underneath the bulge, pushing the bulge ahead of the Moon -- the tidal bulge then has a gravitational pull of its own on the Moon. This effect boosts the Moon in orbit. Meanwhile, the friction of the tidal bulge on the Earth's rotation causes the Earth to very slightly slow down.Therefore, because of the effects of the Moon's revolution around the Earth, the Earth's day is getting slightly longer, and the Moon is getting slightly farther away from Earth.
Earth.
Based on what? If you know the radius, you can use the formula for a sphere - which is a good approximation in the case of Earth and Moon.
The moon's gravitational pull causes a bulge in the Earth's oceans by attracting water towards it, creating high tides.
Gravity behaves exactly the same on the moon as it does on earth. The formula that's used to calculate the gravitational force between two masses is the same formula everywhere. Using that formula, it's easy to calculate that any object weighs about 1/6th as much on the moon as it weighs on the earth.
A lunar bulge is a deformation of Earth's oceans caused by the gravitational pull of the Moon. As the Moon orbits Earth, its gravity creates a bulge on the side of Earth that is closest to it, as well as a smaller bulge on the opposite side due to the centrifugal force generated by the Earth-Moon system's rotation. This phenomenon contributes to the rise and fall of ocean tides, with the bulges corresponding to high tide areas.