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The astronomical unit is a unit of length approximately equal to the distance from the Earth to the Sun. The currently accepted value of the AU is 149,597,870,691 ± 30 metres, nearly 150 million kilometres or 93 million miles.

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What is earth distance from the sun in au?

1 AU, by definition.


1 au is equal many meter?

== == Since 1 au is about 150 million killometer, 1 au is equal to about 150,000,000,000 meters.


How many AU's from the planets to the sun?

Mercury--Sun= AU Venus--Sun= AU Earth--Sun=1 AU Mars--Sun= AU Jupiter--Sun= AU Saturn--Sun= AU Uranus--Sun= AU Neptune--Sun= AU Pluto--Sun= AU


If the sun is 1 AU what is the radius of Antares on AU?

The Earth is 1 AU from the Sun, not the diameter. See related question.


How far are AU's?

AU stands for Astronomical Unit. The Earth is 1 AU away from the sun. Therefore, 1 AU is approximately 93 million miles long.


How many gold atoms would there be in 328 milligrams of gold?

1g AU = 1000mg Au 1 mole Au = 196.96655g Au 1 mole Au = 6.022 X 1023 atoms Au Calculation: 328mg Au x (1g Au /1000g Au) x (1 mole Au/196.97g Au) x (6.022 X 1023 atoms Au/1mole Au) = 1.00 x 1021 atoms Au


is an au 11340000 miles?

1 AU is 92,956,000 miles.


How are au compare to kilometers?

1 AU = 149,597,871 kilometers.


How many AU are in 4.7Ly?

1 light year is approximately 63,241 AU. Therefore, 4.7 light years is about 297,116 AU.


What is the length of 1?

The astronomical unit is a unit of length approximately equal to the distance from the Earth to the Sun. The currently accepted value of the AU is 149,597,870,691 ± 30 metres, nearly 150 million kilometres or 93 million miles.


What is the abbreviation for astronomical unit?

The abbreviation for astronomical unit is AU. An astronomical unit is a unit of length roughly equal to the average distance from the Earth to the Sun, used to measure distances within our solar system.


A comet moves in an elliptical orbit around the sun its distance from the sun varies between 1 AU and 7 AU Calculate its orbital period?

Major axis of mentioned comet has length of 8 AU (1 AU at perihelion plus 7 AU at apohelion on the opposite side of Sun). According to Kepler's third law, the square of orbital period is directly proportional to cube of the orbit's major axis. When using astronomical units for distance and sidereal years for time, this simplifies to: T2 = a3, where T - orbital period a - length of major axis We can then calculate that T for a = 8 AU is about 22.62 years.