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Q: What is the voltage of the electrochemical cell written as Cu(s) Cu2 (aq) Mg2 (aq) Mg(s)?
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What is the function of a salt bridge in a voltaic cell?

A salt bridge is an important component of an electrochemical cell. This type of cell can produce an electric current as a product of a chemical reaction type known as oxidation-reduction (also known as redox). The cell reaction is divided into two parts: oxidation (electron loss) and reduction (electron gain). The salt bridge exists to provide the electrical connection between the two reaction vessels while keeping the two reactions separate. The salt bridge allows the electron transfer between the two vessels.


Does anode gain mass?

I'm not completely certain about this but I'm convinced that an anode actually loses mass. For example, in the cell equations for an Ag(s) cathode being dipped into an AgNO3 solution, connected to a Cu(s) anode being dipped into a Cu(NO3)2 solition, 2Ag+(aq) + 2e- -> 2Ag(s) (Cathode 1/2 reaction, reduction) Cu(s) -> Cu2+(aq) +2e- (Anode 1/2 reaction, oxidation) , the cathode reaction is taking the Ag+(aq) ions in the AgNO3- solution and turning them into solid silver, Ag(s). Therefore, I believe it is correct to assume that solid silver is being formed in the cathode solution. The anode half reaction however is the opposite, taking a solid copper atom, Cu(s), and turning it into an aqueous copper cation, Cu2+(aq). This leads me to believe that the copper rod (anode) is losing mass. So, I believe the cathode is gaining mass and the anode is losing mass.


Why do you heat substanses with Benedict's reagent with them while testing?

Answer:- It requires energy for the Cu2+ ions in the Benedicts to be reduced to Cu+ Explanation:- Benedicts reagent indicates a reducing sugar because it consists of copper (II) sulphate in an alkaline solution. Its distinctive blue colour turns brick red when it is added to a reducing agent because the Cu2+ ions will be reduced, resulting in copper (I) sulphate, which is brick red. This is where the term "reducing sugars" comes from. All sugars that reduce the benedicts have an available aldehyde or ketone group. It is this group that provides the electron needed to reduce the Benedict's. Because of ionisation energies, even when the reducing sugar is present energy is required to remove the electron from the valence shell. This is why heat is required. It does not, as the previous answer stated, have anything to do with enzymes. Enzymes are globular protein molecules whereas saccharides are ring structured carbohydrate molecules. Do not use any of that answer in any work you might do!


Does Copper have a simple or giant structure?

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What is preferential discharge of ions during electrolysis and what are they?

The preferential discharge of ions is affected by the kind of electrode used in the reaction and also the concentration of the ions in the solution this especially pertains to solutions containing halides

Related questions

What is the voltage of the electrochemical cell written as Cus Cu2 aq Mg2 aq Mgs?

5


What is the voltage of the electrochemical cell written as Cu's Cu2 aq Mg2 aq Mg's?

-2.71v


What is the voltage of the electrochemical cell written as Cu(s) Cu2 (aq) Mg2 (aq) Mg (s)?

-2.71v


Which is a possible electrochemical cell?

Cr(s) Cr3+(aq) Ag+(aq) Ag(s) Cu(s) Cu2+(aq) Sn4+(aq), Sn2+(aq) Pt(s)


What is the voltage of the cell shown?

Cu(s) | Cu2+(aq) K+(aq) | K(s)-3.27Zn(s) | Zn2+(aq) Na+(aq) | Na(s)-1.95


Calculate the standard emf of a cell that uses the Mg Mg2 plus and Cu Cu2 plus half cell reactions at 25 degrees C?

Cu + Mg2 --------> Cu2 + Mg Cu --------------> Cu2 + 2e Mg2 + 2e --------> Mg Cu --------------> Cu2 + 2e (E = +0.35) Mg2 + 2e --------> Mg (E = -2.36V) +0.35 + (-2.36) = -2.01V --------------------------------------… Mg + Cu2 --------> Mg2 + Cu Mg --------------> Mg2 + 2e Cu2 + 2e --------> Cu Mg --------------> Mg2 + 2e (E = +2.36V) Cu2 + 2e --------> Mg (E = -0.35V) +2.36 + (-0.35) = +2.01V


What is the overall voltage for a redox reaction with the half reactions Ag e Ag and Cu2 2e?

0.80-0.34


What is the overall voltage for a redox reaction with the half reactions Mg s -- Mg2 plus plus 2e- and Cu2 plus -- Cu s?

The overall voltage for a redox reaction with the half reactions Mg s -- Mg2 plus plus 2e- and Cu2 plus -- Cu is 76 V.


What is the overall voltage for a redox reaction with the half-reactions Mgs Mg2 2e- and Cu2 2e- Cus?

0.34-(-2.37)


What is the correct cell notation for the reaction 2Au plus aq plus Cus 2Ausplus Cu2 plus aq?

Cu(s) | Cu2+(aq) Au+(aq) | Au(s)


What is the overall voltage for a redox reaction with the half-reactions Mg-> Mg+2 +2e- and Cu2+ +2e- -> Cu?

0.34-(-2.37)


What is the overall voltage for a redox reaction with the half-reactions Mg(s) Mg2 2e- and Cu2 2e- Cu(s)?

0.34-(-2.37)