-2.71v
-2.71 V
A salt bridge is an important component of an electrochemical cell. This type of cell can produce an electric current as a product of a chemical reaction type known as oxidation-reduction (also known as redox). The cell reaction is divided into two parts: oxidation (electron loss) and reduction (electron gain). The salt bridge exists to provide the electrical connection between the two reaction vessels while keeping the two reactions separate. The salt bridge allows the electron transfer between the two vessels.
I'm not completely certain about this but I'm convinced that an anode actually loses mass. For example, in the cell equations for an Ag(s) cathode being dipped into an AgNO3 solution, connected to a Cu(s) anode being dipped into a Cu(NO3)2 solition, 2Ag+(aq) + 2e- -> 2Ag(s) (Cathode 1/2 reaction, reduction) Cu(s) -> Cu2+(aq) +2e- (Anode 1/2 reaction, oxidation) , the cathode reaction is taking the Ag+(aq) ions in the AgNO3- solution and turning them into solid silver, Ag(s). Therefore, I believe it is correct to assume that solid silver is being formed in the cathode solution. The anode half reaction however is the opposite, taking a solid copper atom, Cu(s), and turning it into an aqueous copper cation, Cu2+(aq). This leads me to believe that the copper rod (anode) is losing mass. So, I believe the cathode is gaining mass and the anode is losing mass.
Answer:- It requires energy for the Cu2+ ions in the Benedicts to be reduced to Cu+ Explanation:- Benedicts reagent indicates a reducing sugar because it consists of copper (II) sulphate in an alkaline solution. Its distinctive blue colour turns brick red when it is added to a reducing agent because the Cu2+ ions will be reduced, resulting in copper (I) sulphate, which is brick red. This is where the term "reducing sugars" comes from. All sugars that reduce the benedicts have an available aldehyde or ketone group. It is this group that provides the electron needed to reduce the Benedict's. Because of ionisation energies, even when the reducing sugar is present energy is required to remove the electron from the valence shell. This is why heat is required. It does not, as the previous answer stated, have anything to do with enzymes. Enzymes are globular protein molecules whereas saccharides are ring structured carbohydrate molecules. Do not use any of that answer in any work you might do!
copper is an element, so in terms of molecular structure, it extremely simple(Cu or Cu2) In terms of atomic structure and electron/proton/neutron configuration it is obviously more complex.It contains 29 protons and electrons, an 35 neutrons. Finally, in terms of crystal structure, its pretty simple because it is face-centered cubic
The preferential discharge of ions is affected by the kind of electrode used in the reaction and also the concentration of the ions in the solution this especially pertains to solutions containing halides
5
-2.71v
-2.71v
Cr(s) Cr3+(aq) Ag+(aq) Ag(s) Cu(s) Cu2+(aq) Sn4+(aq), Sn2+(aq) Pt(s)
Cu(s) | Cu2+(aq) K+(aq) | K(s)-3.27Zn(s) | Zn2+(aq) Na+(aq) | Na(s)-1.95
Cu + Mg2 --------> Cu2 + Mg Cu --------------> Cu2 + 2e Mg2 + 2e --------> Mg Cu --------------> Cu2 + 2e (E = +0.35) Mg2 + 2e --------> Mg (E = -2.36V) +0.35 + (-2.36) = -2.01V --------------------------------------… Mg + Cu2 --------> Mg2 + Cu Mg --------------> Mg2 + 2e Cu2 + 2e --------> Cu Mg --------------> Mg2 + 2e (E = +2.36V) Cu2 + 2e --------> Mg (E = -0.35V) +2.36 + (-0.35) = +2.01V
0.80-0.34
The overall voltage for a redox reaction with the half reactions Mg s -- Mg2 plus plus 2e- and Cu2 plus -- Cu is 76 V.
0.34-(-2.37)
Cu(s) | Cu2+(aq) Au+(aq) | Au(s)
0.34-(-2.37)
0.34-(-2.37)