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What is the overall voltage for the nonspountanious redox reaction involving Mg and Cu and their ions?
In the nonspontaneous redox reaction involving magnesium (Mg) and copper (Cu), the overall voltage (or electromotive force, EMF) can be determined using standard reduction potentials. The standard reduction potential for Cu²⁺/Cu is +0.34 V, while for Mg²⁺/Mg it is -2.37 V. The overall voltage for the reaction, calculated by subtracting the reduction potential of magnesium from that of copper, is approximately +2.73 V. However, since the reaction is nonspontaneous, the voltage indicates that an external energy source is required to drive the reaction.
What is the overall voltage for a redox reaction with the half reactions Ag e Ag s and Cu s Cu2 2e?
The overall voltage for the redox reaction involving Ag and Cu is determined by subtracting the reduction potential of the anode from the reduction potential of the cathode. Given the reduction potentials of Ag and Cu as 0.80 V and 0.34 V respectively, the overall voltage is 0.46 V, calculated as (0.34 V) - (0.80 V).
What is overall voltage for a redox reaction with the half reactions Mg(s) Mg2 plus 2e Cu(s)?
To determine the overall voltage for the redox reaction involving the half-reactions ( \text{Mg}(s) \rightarrow \text{Mg}^{2+} + 2e^- ) and ( \text{Cu}^{2+} + 2e^- \rightarrow \text{Cu}(s) ), you first need the standard reduction potentials. The standard reduction potential for ( \text{Cu}^{2+}/\text{Cu} ) is +0.34 V and for ( \text{Mg}^{2+}/\text{Mg} ) is -2.37 V. The overall voltage is calculated by subtracting the oxidation potential of magnesium from the reduction potential of copper: ( 0.34 , \text{V} - (-2.37 , \text{V}) = 2.71 , \text{V} ). Thus, the overall voltage for the redox reaction is 2.71 V.
What is the overall voltage for the non spontaneous redox reaction Mg and Cu and their ions?
For the non-spontaneous redox reaction between magnesium (Mg) and copper ions (Cu²⁺), the overall cell voltage can be calculated using standard electrode potentials. The standard reduction potential for Cu²⁺/Cu is +0.34 V, while for Mg²⁺/Mg it is -2.37 V. The overall cell potential (E°) for the reaction is E° = E°(reduction) - E°(oxidation) = +0.34 V - (-2.37 V) = +2.71 V. However, since the reaction is non-spontaneous, the cell voltage would be negative under standard conditions, indicating that external energy is required to drive the reaction.
What is the overall redox reaction of cr2o7 plus br?
The overall redox reaction of Cr2O7 + Br is not a balanced equation. To balance the equation, the half-reactions for the oxidation and reduction of each element need to be determined and balanced first.
What is the overall voltage for a redox reaction with the half-reaction Mg s Mg2 2e- and Cu2 2e- Cu s?
0.34 - (-2.37) you're welcome.
What is the overall voltage for a redox reaction with the half-reactions Mgs Mg2 2e- and Cu2 2e- Cus?
0.34-(-2.37)
What is the overall voltage for the nonspountanious redox reaction involving Mg and Cu and their ions?
In the nonspontaneous redox reaction involving magnesium (Mg) and copper (Cu), the overall voltage (or electromotive force, EMF) can be determined using standard reduction potentials. The standard reduction potential for Cu²⁺/Cu is +0.34 V, while for Mg²⁺/Mg it is -2.37 V. The overall voltage for the reaction, calculated by subtracting the reduction potential of magnesium from that of copper, is approximately +2.73 V. However, since the reaction is nonspontaneous, the voltage indicates that an external energy source is required to drive the reaction.
What is the overall voltage for a redox reaction with the half-reactions Mg-> Mg+2 +2e- and Cu2+ +2e- -> Cu?
0.34-(-2.37)
What is the overall voltage for the non spontaneous redox reaction involving Mg and Cu and their irons?
The overall voltage for the non-spontaneous redox reaction between Mg and Cu can be calculated by finding the difference in standard reduction potentials between the two half-reactions. The standard reduction potentials for Mg and Cu are -2.37 V and 0.34 V, respectively. Therefore, the overall voltage would be (-2.37 V) - (0.34 V) = -2.71 V.
What is the overall voltage for the nonspontaneous redox reaction involving mg and cu and their ions?
-2.37 - 0.34
What is the overall voltage for a redox reaction with the half reactions Ag e Ag s and Cu s Cu2 2e?
The overall voltage for the redox reaction involving Ag and Cu is determined by subtracting the reduction potential of the anode from the reduction potential of the cathode. Given the reduction potentials of Ag and Cu as 0.80 V and 0.34 V respectively, the overall voltage is 0.46 V, calculated as (0.34 V) - (0.80 V).
What is the overall voltage for a redox reaction with the half-reactions Mg s Mg2 2e- and Cu2 2e- Cu s?
0.34 - (-2.37) you're welcome.
What is the overall voltage for a redox reaction with the half reactions Ag e Ag and Cu2 2e?
0.80-0.34
What is overall voltage for a redox reaction with the half reactions Mg(s) Mg2 plus 2e Cu(s)?
To determine the overall voltage for the redox reaction involving the half-reactions ( \text{Mg}(s) \rightarrow \text{Mg}^{2+} + 2e^- ) and ( \text{Cu}^{2+} + 2e^- \rightarrow \text{Cu}(s) ), you first need the standard reduction potentials. The standard reduction potential for ( \text{Cu}^{2+}/\text{Cu} ) is +0.34 V and for ( \text{Mg}^{2+}/\text{Mg} ) is -2.37 V. The overall voltage is calculated by subtracting the oxidation potential of magnesium from the reduction potential of copper: ( 0.34 , \text{V} - (-2.37 , \text{V}) = 2.71 , \text{V} ). Thus, the overall voltage for the redox reaction is 2.71 V.
What is the overall voltage for the non spontaneous redox reaction Mg and Cu and their ions?
For the non-spontaneous redox reaction between magnesium (Mg) and copper ions (Cu²⁺), the overall cell voltage can be calculated using standard electrode potentials. The standard reduction potential for Cu²⁺/Cu is +0.34 V, while for Mg²⁺/Mg it is -2.37 V. The overall cell potential (E°) for the reaction is E° = E°(reduction) - E°(oxidation) = +0.34 V - (-2.37 V) = +2.71 V. However, since the reaction is non-spontaneous, the cell voltage would be negative under standard conditions, indicating that external energy is required to drive the reaction.
What happens to a redox reaction when it is shown as a half-reaction?
The redox reaction is split into its oxidation part and it’s reduction part
