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What would the equilibrium concentration of NO be in a gas mixture that contains 1.7 M SO3 0.070 M SO2 and 1.3 M NO2 if Keq 10.8 at those conditions?
PaigeLorenzegp3284
SO3 + NO <==> SO2 + NO2
1.7M + xM |=| 0.070M + 1.3M
Keq = 10.8 = [SO2]*[NO2] / [SO3]*[NO] = 0.070*1.3 / 1.7*x
Solving x (concentration NO at eq.) 10.8 * (1.7*x) = 0.070*1.3
x = 0.0091 / 18.36 = 0.000496 = 0.00050 M = 0.50 mM
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∙ 8y ago
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