YR and Yr
The human gametes are Male gametes are sperm and female gametes are eggs. And the gametes chromosome numbers are 42.
Reproductive cells or gametes.
Gametes require half the number of chromosomes of a somatic (regular) cell as gametes are the sex cells. When gametes combine to make a zygote (a fertilised cell), the complete number of chromosomes will be present.
4 haploid cells
Male gametes are made in the testis. male gametes are more-often called sperm.
4
a hypothesis of getting an offspring with 3:1 ratio Mendel have found that only independent assortment works because independent assortment could predict all of the phenotypic appearances for example, 1) when two true-breading peas cross YYRR*yyrr "Y=yellow, y=green", "R=round, r=wrinkled" 2) all of their offsprings in the First Generation will be YyRr, then when those also cross YyRr*YyRr 3)the result in Second Generation will be in a ratio of 3:1 and the phenotype will be 25% YYRR "yellow-round" 50% YyRr "yellow-round" 25% yyrr "green-wrinkled" Which after all cannot be true because some of the other possible phynotypes are not shown such as Yyrr "yellow-wrinkled" or yyRr "green-round" That's why Mendel thought that independent assortment represents wider and phenotypes Resource from: Biology author:Campbell.Reece, 8th edition thanks
Using a Punnett square, you can calculate the genotype and phenotype of two dihybrid plants. For example, if you have two heterozygous individuals for two dominant traits (we'll pretend the genotype is YyRr), put them into a Punnett square, and you'll get these results: YYRR: 1, YYRr: 2, YYrr: 1 YyRR: 2, YyRr: 4, Yyrr: 2 yyRR: 1, yyRr: 2, yyrr: 1 Phenotypes expressed: Dominant for both traits: 9/16 Dominant for trait 1: 3/16 Dominant for trait 2: 3/16 Recessive for both traits: 1/16 Therefore, the ratio would be 9:3:3:1
The possible gametes produced by an individual with the genotype Ww will be W and w.
Gametes produced by crossing over are called non parental and possess more genetic variations as compared to those produced with out crossing over which possess much less genetic variations.
1:3:1 3:1 9:3:3:1 4:1
That they won't be identical to each other.
A gamete is haploid (1N) so 'Aa' & 'AA' are diploid and during cell division (mitosis) gametes are formed and then 2 gametes merge together to make a diploid (think of sperm and egg, each is haploid or 1N, when fertilization occurs the egg and sperm form 1 cell that is 2N or diploid). So the possible gametes for 'Aa' would be 'A' & 'a' while for 'AA' the only gametes possible are 'A' If the question is asking what the possible gametes are for 'AaBB' the haploid (gamete) can be 'AB' or 'aB'
The possible gametes are ABDEf, aBDEf, ABDef, and aBDef.
This is because during meiosis there is (mostly) genetic variation by means of crossing over, independent assortment and mutations. As two gametes are being fused, the end product will be different from the parent, because the factors mentioned above ensure this. For a bit more info: The end product might not always be different as sometimes (in a very rare case), independent assortment and mutations might not occur to the two gametes which are to be fertilised, and if the two gametes both contained chromosomes on which crossing over did not occur, and if these two gametes were to fertilise, then the product would be genetically the same as the parent plant.
Crossing over and random alignment of chromosomes
A punnett square