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What is a c program to implement trapezoidal and Simpson's methods?

ITS EASY...TRY THIS OUT..TRAPEZOIDAL METHOD#include#include#includefloat valcal(float x){return (x*x*x);}int main(){float a,b,h,c,I;int n,i;printf("THE TRAPEZOIDAL RULE:\n");printf("---------------------");printf("\n\n\nEnter the two limits and the no. of divisions:\n");scanf("%f %f %d",&a, &b, &n);h=(b-a)/n;//printf("\nVALUE of h: %f\n", h);c=a;I=valcal(a)+valcal(b);//printf("\nVALUE FOR a: %f\n", valcal(a));//printf("\nVALUE FOR b: %f\n", valcal(b));for(i=1;i=b){printf("\n\nc>b\n\n");break;}//printf("\nVALUE FOR %f: is %f\n",c, valcal(c));I=I+(2*valcal(c));//printf("\nI right now is %f", I);}printf("\n\n\nThe integration of x*x*x is: %f",(h*I)/2);printf("\n\n\n");system("pause");}SIMPSON'S 1/3RD METHOD#include#include#includefloat valcal(float x){return (1/(1+x*x));}int main(){float a,b,h,c,I;int n,i;printf("THE SIMPSON'S ONE-THIRD RULE:\n");printf("------------------------------");printf("\n\n\nEnter the two limits and the no. of divisions:\n");scanf("%f %f %d",&a, &b, &n);h=(b-a)/n;//printf("\nVALUE of h: %f\n", h);c=a;I=valcal(a)+valcal(b);//printf("\nVALUE FOR a: %f\n", valcal(a));//printf("\nVALUE FOR b: %f\n", valcal(b));for(i=1;ib){printf("\n\nc>b\n\n");break;}//printf("\nVALUE FOR %f: is %f\n",c, valcal(c));if(i%2==0)I=I+(2*valcal(c));elseI=I+4*valcal(c);//printf("\nI right now is %f", I);}printf("\n\n\nThe integration of x*x*x is: %f",(h*I)/3);printf("\n\n\n");system("pause");}NEED MORE HELP...MAIL ME YOUR PROB... SEE YA


What words can be made with these letters h j f e e o b b h q a n?

beef


Write a program to find the value the integration 1by1plus X between the limits 0 and 1 through trapezoidal rule?

#include<stdio.h> #include<conio.h> #include<math.h> float f(float x) { float y; if(x!=0) //y=sin(x)-log(x)+exp(x); y=1/(1+x); else printf("answer can not be derived"); return(y); } float g(float x) { float k; k=(-2)/(pow((1+x),3)); return(k); } void main() { float i,n,k,z,s=0,err=0; float h,x,a[100],b,c; clrscr(); printf("\n enter the range of the integration"); scanf("%f%f",&b,&c); printf("\n enter n so to divide the range into n parts"); scanf("%f",&n); h=(c-b)/n; printf("\n\n%f",h); k=(f(b)+f(c)); printf("\nk=%f\n\n",k); for(i=b+h;i<c;i+=h) { z+=f(i); printf("\n%f",z); } s=(h*(k+2*z))/2; printf("\n\n the value of the integration=%f\n\n",s); for(i=b;i<=c;i+=h) err+=g(i); err=(err*(pow(h,3)))/12; printf("\n\n approximate error= %f\n\n",err); getch(); }here...


Why is o?

a b c d e f g h i j k l m n OOOOOOOOOOOOOOO a b c d e f g h i j k l m n OOOOOOOOOOOOOOO


What is the c programmind code for simpsons one third rule to evaluate integrals?

#include<stdio.h> #include<conio.h> #include<math.h> #define f(x) (sin(x*x)) void main() { float a,b,h,x,s,n,aaa,h1,h2,p=0.0,p1=0.0,pp,sum,k,i=0.0; int j=1,co; clrscr(); printf("\n Plese Enter lower limit :"); scanf("%f",&a); printf("\n Plese Enter upper limit :"); scanf("%f",&b); printf("\n Plese Enter the number of Intervales::"); scanf("%f",&n); h=(b-a)/n; //Calculiting the value of h printf("The ..................=%f",h); x=a+h; s=f(a)+f(b); //Calculiting the First term & last term while(j<n) { if((j%2)==0) //checking even and odd terms i=i+(2*f(x)); //Calculiting the even terms else i=i+(4*f(x)); //Calculiting the odd terms x=x+h; j++; } i=(h/3)*(i+s); //putting all data in to the formula printf("\nThe value of the integral is %f",i); // part is for Error calculation h1=b-h; h2=a+h; pp=(7*(f(h2)+f(h1))); sum=a-h; k=b+h; x=a+(2*h); for(co=2;co<n-2;co++) { if(co%2==0) p=p+(f(x)); else p1=p1+(f(x)); x=x+h; } aaa=(-(h/90))*( ( f(sum)+f(k) )-4*(s) +7*( f(h1) )-(8*p)+(8*p1) ); printf("\nThe Error is= %f",aaa); getch(); }


How do you make a calculator in code block by using c?

#include<stdio.h> #include<conio.h> int main(void) { float a,b,c=0, d=0, e=0,f=0; printf("Please enter two numbers:\n"); scanf("%f %f", &a, &b); c=a+b; d=a-b; e=a*b; f=a/b; printf("The sum of %f and %f is :%f\n", a,b,c); printf("The subtraction of %f and %f is :%f\n", a,b,d); printf("The multiplication of %f and %f is :%f\n", a,b,e); printf("The division of %f by %f is :%f\n",a,b,f); getch(); }


Which letters have a sloping straight line?

B, D, E, F, H, I, K, L, M, N, P, R, T, (As capitals) b, d, h, i, k, l, m, n, p, q, r, (as small letters)


What 6 letter words can be spelled by f h m d b y h t n r d?

The only English word is rhythm.


What words have h v n n r f q o?

Some words that you can make with H V N N R F Q O are:hornforfrohononorofohonor


Enter the follow bonds in order of increasing bond stretching frequency C-H F-H O-H N-H?

The bond stretching frequency increases with increasing bond strength. Therefore, the order of increasing bond stretching frequency is: F-H < O-H < N-H < C-H.


How do you use quotientrule to find the slope tangent to a curve?

The quotient rule tells says that: If: f(x) = g(x) / h(x) Then: f'(x) = (g'(x) · h(x) - g(x) · h'(x)) / h(x)2 That derivative gives you the slope of the original curve's tangent at any given x-coordinate. For example, if: f(x) = axn / bxm then: f'(x) = (anxn-1 · bxm - axn · bmxm - 1) / b2x2m This of course simplifies considerably, due to the simplicity of the original function: = (abnxm+n-1 - abmxm+n-1) / b2x2m = (n - m)abxm+n-1 / b2x2m = (n - m)axn-m-1 / b = (n - m)(a/b)xn-m-1 Which makes perfect sense if you rearrange our initial function and take it's derivative in a simpler manner: f(x) = axn / bxm f(x) = (a/b)xn-m f'(x) = (n-m)(a/b)xn-m-1


What are some eight letter words with 1st letter B and 3rd letter N and 5th letter F and 7th letter S and 8th letter H?

According to SOWPODS (the combination of Scrabble dictionaries used around the world) there are 1 words with the pattern B-N-F-SH. That is, eight letter words with 1st letter B and 3rd letter N and 5th letter F and 7th letter S and 8th letter H. In alphabetical order, they are: bonefish