4406 height in a feet of ben nevis
In English, there are 21 consonants: B, C, D, F, G, H, J, K, L, M, N, P, Q, R, S, T, V, W, X, Y, Z. Note that Y can sometimes act as a vowel. This number can vary depending on the language being considered.
A- Auckland B- Brisbane C- cambridge d- dunedin e- edinburgh f- freetown... (thats a real place... in south africa) g- A- Auckland B- Brisbane C- cambridge d- dunedin e- edinburgh f- freetown... (thats a real place... in south africa) g-
An antonym of "border state" could be "landlocked state." A landlocked state is one that is surrounded by other states or countries and does not have a border with an ocean or sea.
The driving distance between Cape Coral and Tampa Bay Airport is approximately 140 miles, which usually takes around two and a half hours to cover by car, depending on traffic conditions.
The distance from Tifton, GA to Macon, GA is approximately 102 miles. It takes around 1.5 to 2 hours to drive between the two cities.
ITS EASY...TRY THIS OUT..TRAPEZOIDAL METHOD#include#include#includefloat valcal(float x){return (x*x*x);}int main(){float a,b,h,c,I;int n,i;printf("THE TRAPEZOIDAL RULE:\n");printf("---------------------");printf("\n\n\nEnter the two limits and the no. of divisions:\n");scanf("%f %f %d",&a, &b, &n);h=(b-a)/n;//printf("\nVALUE of h: %f\n", h);c=a;I=valcal(a)+valcal(b);//printf("\nVALUE FOR a: %f\n", valcal(a));//printf("\nVALUE FOR b: %f\n", valcal(b));for(i=1;i=b){printf("\n\nc>b\n\n");break;}//printf("\nVALUE FOR %f: is %f\n",c, valcal(c));I=I+(2*valcal(c));//printf("\nI right now is %f", I);}printf("\n\n\nThe integration of x*x*x is: %f",(h*I)/2);printf("\n\n\n");system("pause");}SIMPSON'S 1/3RD METHOD#include#include#includefloat valcal(float x){return (1/(1+x*x));}int main(){float a,b,h,c,I;int n,i;printf("THE SIMPSON'S ONE-THIRD RULE:\n");printf("------------------------------");printf("\n\n\nEnter the two limits and the no. of divisions:\n");scanf("%f %f %d",&a, &b, &n);h=(b-a)/n;//printf("\nVALUE of h: %f\n", h);c=a;I=valcal(a)+valcal(b);//printf("\nVALUE FOR a: %f\n", valcal(a));//printf("\nVALUE FOR b: %f\n", valcal(b));for(i=1;ib){printf("\n\nc>b\n\n");break;}//printf("\nVALUE FOR %f: is %f\n",c, valcal(c));if(i%2==0)I=I+(2*valcal(c));elseI=I+4*valcal(c);//printf("\nI right now is %f", I);}printf("\n\n\nThe integration of x*x*x is: %f",(h*I)/3);printf("\n\n\n");system("pause");}NEED MORE HELP...MAIL ME YOUR PROB... SEE YA
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#include<stdio.h> #include<conio.h> #include<math.h> float f(float x) { float y; if(x!=0) //y=sin(x)-log(x)+exp(x); y=1/(1+x); else printf("answer can not be derived"); return(y); } float g(float x) { float k; k=(-2)/(pow((1+x),3)); return(k); } void main() { float i,n,k,z,s=0,err=0; float h,x,a[100],b,c; clrscr(); printf("\n enter the range of the integration"); scanf("%f%f",&b,&c); printf("\n enter n so to divide the range into n parts"); scanf("%f",&n); h=(c-b)/n; printf("\n\n%f",h); k=(f(b)+f(c)); printf("\nk=%f\n\n",k); for(i=b+h;i<c;i+=h) { z+=f(i); printf("\n%f",z); } s=(h*(k+2*z))/2; printf("\n\n the value of the integration=%f\n\n",s); for(i=b;i<=c;i+=h) err+=g(i); err=(err*(pow(h,3)))/12; printf("\n\n approximate error= %f\n\n",err); getch(); }here...
a b c d e f g h i j k l m n OOOOOOOOOOOOOOO a b c d e f g h i j k l m n OOOOOOOOOOOOOOO
#include<stdio.h> #include<conio.h> #include<math.h> #define f(x) (sin(x*x)) void main() { float a,b,h,x,s,n,aaa,h1,h2,p=0.0,p1=0.0,pp,sum,k,i=0.0; int j=1,co; clrscr(); printf("\n Plese Enter lower limit :"); scanf("%f",&a); printf("\n Plese Enter upper limit :"); scanf("%f",&b); printf("\n Plese Enter the number of Intervales::"); scanf("%f",&n); h=(b-a)/n; //Calculiting the value of h printf("The ..................=%f",h); x=a+h; s=f(a)+f(b); //Calculiting the First term & last term while(j<n) { if((j%2)==0) //checking even and odd terms i=i+(2*f(x)); //Calculiting the even terms else i=i+(4*f(x)); //Calculiting the odd terms x=x+h; j++; } i=(h/3)*(i+s); //putting all data in to the formula printf("\nThe value of the integral is %f",i); // part is for Error calculation h1=b-h; h2=a+h; pp=(7*(f(h2)+f(h1))); sum=a-h; k=b+h; x=a+(2*h); for(co=2;co<n-2;co++) { if(co%2==0) p=p+(f(x)); else p1=p1+(f(x)); x=x+h; } aaa=(-(h/90))*( ( f(sum)+f(k) )-4*(s) +7*( f(h1) )-(8*p)+(8*p1) ); printf("\nThe Error is= %f",aaa); getch(); }
#include<stdio.h> #include<conio.h> int main(void) { float a,b,c=0, d=0, e=0,f=0; printf("Please enter two numbers:\n"); scanf("%f %f", &a, &b); c=a+b; d=a-b; e=a*b; f=a/b; printf("The sum of %f and %f is :%f\n", a,b,c); printf("The subtraction of %f and %f is :%f\n", a,b,d); printf("The multiplication of %f and %f is :%f\n", a,b,e); printf("The division of %f by %f is :%f\n",a,b,f); getch(); }
B, D, E, F, H, I, K, L, M, N, P, R, T, (As capitals) b, d, h, i, k, l, m, n, p, q, r, (as small letters)
The only English word is rhythm.
Some words that you can make with H V N N R F Q O are:hornforfrohononorofohonor
The bond stretching frequency increases with increasing bond strength. Therefore, the order of increasing bond stretching frequency is: F-H < O-H < N-H < C-H.
The quotient rule tells says that: If: f(x) = g(x) / h(x) Then: f'(x) = (g'(x) · h(x) - g(x) · h'(x)) / h(x)2 That derivative gives you the slope of the original curve's tangent at any given x-coordinate. For example, if: f(x) = axn / bxm then: f'(x) = (anxn-1 · bxm - axn · bmxm - 1) / b2x2m This of course simplifies considerably, due to the simplicity of the original function: = (abnxm+n-1 - abmxm+n-1) / b2x2m = (n - m)abxm+n-1 / b2x2m = (n - m)axn-m-1 / b = (n - m)(a/b)xn-m-1 Which makes perfect sense if you rearrange our initial function and take it's derivative in a simpler manner: f(x) = axn / bxm f(x) = (a/b)xn-m f'(x) = (n-m)(a/b)xn-m-1
According to SOWPODS (the combination of Scrabble dictionaries used around the world) there are 1 words with the pattern B-N-F-SH. That is, eight letter words with 1st letter B and 3rd letter N and 5th letter F and 7th letter S and 8th letter H. In alphabetical order, they are: bonefish