To determine how many 1x4 boards are needed to wrap a 22-inch octagon that is 34 inches tall, first calculate the perimeter of the octagon. The perimeter is 22 inches multiplied by 8 sides, totaling 176 inches. To find out how many 1x4 boards (which are typically 3.5 inches wide) are required, divide the total perimeter (176 inches) by the width of one board (3.5 inches), which equals approximately 50.29. Therefore, you would need 51 boards to wrap the octagon.
One side of a square is 10 inches long. How many one square inch tiles are needed to cover its area?
A 1.25-inch diameter circle contains 1.227 square inches.
A circle with a 14 inch diameter has an area of 153.9 sq inches.
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A 4.75-inch diameter circle contains 17.72 square inches.
39 inches
19
16 if them.
128 cm = 50.394 inches.
To calculate how many 16-inch by 16-inch bricks are needed for a 12 ft. x 16 ft. patio, first convert the patio dimensions to inches: 12 ft. = 144 inches and 16 ft. = 192 inches. The area of the patio is 144 inches × 192 inches = 27,648 square inches. Each brick has an area of 16 inches × 16 inches = 256 square inches. Finally, divide the patio area by the brick area: 27,648 ÷ 256 = 108 bricks needed.
The perimeter of a square is 100 inches. How many square tiles 1 inch on each edge are needed to cover its area?
If the table height is 29 inches standard then 96 inches is perfect fit which gives the drop up to the floor.
288 of them.
To determine how many 16 x 16 inch pavers are needed for a 20 x 20 ft patio, first convert the patio dimensions to inches: 20 ft = 240 inches. The area of the patio is 240 inches x 240 inches = 57,600 square inches. Each 16 x 16 inch paver covers 256 square inches. Dividing the total patio area by the area of one paver gives 57,600 / 256 = 225 pavers needed.
One piece will suffice.
1 inch above 61 inches is 62 inches
There are no square inches in an inch. Square inches are units of area and inches are units of length.