Suppose: B- is symbol for any (soluble) base.
Equilibrium of a base when diluted in water:
B- + H2O <==> HB + OH-
Equilibrium constant:
Keq = [HB] * [OH-] / [B-] * [H2O]
The base dissociation contant is defined by:
KB = [HB]*[OH-]/[B-]So, KB = Keq*[H2O] = Keq*55.6 mol/L
He was in hospital for a respiratory infection.
The Le Chtelier's principle states one thing. It is the dynamic equilibrium which is disturbed by changing the conditions and the position of equilibrium moves that makes a change.
The reaction would shift to balance the change
The information an acid or base equilibrium constant gives is that the acidity and base levels are equal to the equilibrium constant multi[plied by the water concentration.
pH of a solution tells us about the nature of a solution( i.e acidic or basic ) if pH of a solution is less than 7 tahn it's acidic if it's 7 then it's neutral and more than seven will make it base.
This is called molality.
The dissociation constant is:
k = [H][X]/[HX]
I suppose that the principle of Le Châtelier is not applicable in this case.
These concentrations are supposed to be equal.
pH = -log [H+(aq)]. In words, pH is the negative logarithm (to the base 10) of the hydrogen ion concentration.
Stressing an equilibrium simply means that the physical properties in which already exists are balanced. Stress can be applied by either changing the pressure or the volume or temperature.
A base contain the hydroxyl group (OH)-.
pH=-log[H+]
Edited: it is also pH = 14 - pOH. That is certainly an equation for pH.