Suppose: B- is symbol for any (soluble) base.
Equilibrium of a base when diluted in water:
B- + H2O <==> HB + OH-
Equilibrium constant:
Keq = [HB] * [OH-] / [B-] * [H2O]
The base dissociation contant is defined by:
KB = [HB]*[OH-]/[B-]So, KB = Keq*[H2O] = Keq*55.6 mol/L
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The reaction rate at known reactant concentrations.
some of the acid has dissociated
APEX
The exponents determine how much concentration changes affect the reaction rate
The Le Chtelier's principle states one thing. It is the dynamic equilibrium which is disturbed by changing the conditions and the position of equilibrium moves that makes a change.
The reaction would shift to balance the change
The information an acid or base equilibrium constant gives is that the acidity and base levels are equal to the equilibrium constant multi[plied by the water concentration.
pH of a solution tells us about the nature of a solution( i.e acidic or basic ) if pH of a solution is less than 7 tahn it's acidic if it's 7 then it's neutral and more than seven will make it base.
This is called molality.
The dissociation constant is:
k = [H][X]/[HX]
These concentrations are supposed to be equal.
pH = -log [H+(aq)]. In words, pH is the negative logarithm (to the base 10) of the hydrogen ion concentration.
pH=-log[H+]
Edited: it is also pH = 14 - pOH. That is certainly an equation for pH.