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Is a carrier for colorblindness is colorblind?
Not necessarily. The allele for colorblindness is recessive. For a female, in order to be colorblind she must have to recessive alleles for colorblindness. Example: XcXc would be colorblind. XCXc would be a carrier for colorblindness, but not colorblind. For a male, because colorblindness is a sex-linked gene, he only needs one allele to be colorblind. Example: XcY is colorblind. XCY is not colorblind.
How do you have a colorblind son if neither parent is colorblind?
It is just the DNA lottery. If neither parent is colorblind that just means that one of them (or both of them) have recessive genes for colorblindness that happened to show up in this particular child.
Is colorblindness a disability?
Not necessarily. The allele for colorblindness is recessive. For a female, in order to be colorblind she must have to recessive alleles for colorblindness. Example: XcXc would be colorblind. XCXc would be a carrier for colorblindness, but not colorblind. For a male, because colorblindness is a sex-linked gene, he only needs one allele to be colorblind. Example: XcY is colorblind. XCY is not colorblind.
Why is it not possible to get a colorblind female from a normal male and a heterozygous female?
Color blindness is typically inherited as an X-linked recessive trait. A colorblind female must have two copies of the colorblind allele (one from each parent), meaning she must inherit the allele from both her mother and father. In this scenario, the normal male (with a normal X chromosome) can only pass on a normal X chromosome to his daughters, while the heterozygous female has one normal X and one colorblind X, meaning she can pass on either allele. Therefore, the combination of a normal male and a heterozygous female cannot produce a colorblind daughter.
Why are men more likely than women to be colorblind?
Yes. Because the colorblind trait is a sexlinked trait and is found in the X chromosome that is inherited from the mother, men that only have one X chromosome will develop colorblindness if the trait is found in this gene. For a woman to get it, she would need to have the colorblind gene on both x chromosomes. Therefore the girl´s dad would have to be colorblind and the mother at least a carrier.
What would be the color vision of children if their mom is colorblind and their dad is normal?
Colorblindness is a recessive, sex-linked trait, and the gene that causes it occurs on the X chromosome. For the mother to be colorblind, she must have two copies of the gene and be homozygous recessive. The father, on the other hand, can not have the gene, because he (as a male) only has one X chromosome. So, if we let Xc represent the recessive gene for colorblindness and Xn represent the normal gene, the the mother is XcXc and the father is XnY. All of their children will receive the recessive gene from their mother. In the males, this means that they will be colorblind, because the chromosome they get from their father will by the Y chromosome. The daughters, however, will get the Xn gene, which is dominant and will override the gene for colorblindness. Thus, all of the couple's sons will be colorblind, and none of their daughters will be.
A women wo isn't colorblind but has an allele for color blindness reproduces with a man who has normal vision what is the chance that they'll have a colorblind daughter?
There is no chance for a colorblind daughter because the x-chromosome that comes from the male is normal and then it does not matter which x-chromosome comes from the female because colorblindness is a recessive gene, therefore there is no chance.
Males are more likely to be colorblind than females because?
Males are more likely to be colorblind than females due to the genetic basis of the condition, which is often linked to the X chromosome. Since males have one X and one Y chromosome (XY), a single recessive gene for colorblindness on their X chromosome will result in the condition. In contrast, females have two X chromosomes (XX), so they would need two copies of the recessive gene to be colorblind, making it less likely for them to be affected. This difference in chromosome composition accounts for the higher prevalence of colorblindness in males.
A womens father is colorblind She marries a colorblind man Will there son or daughter be colorblind?
Colorblindness is an X-linked recessive disorder. This means girls (who have the sex chromosomes XX) must have a colorblind X from dad and a colorblind X from mom. Boys only need to have one colorblind X to be colorblind because they have sex chromosomes XY (and have only 1 X). If the dad has it, he has the colorblind X. If the daughter has it, she must have gotten her mom's colorblind X. If the mom is colorblind, then every child they have will be colorblind. If the mom is not colorblind, then she must be a carrier - she must have 1 normal X and 1 colorblind X. Mom is either colorblind (with 2 colorblind Xs) or she is a carrier. Dad is definitely colorblind.
What is the genotype of a carrier of recessive disorder?
A carrier is someone who does not have a disorder but carries the allele on to offspring.
What is the probability a woman heterozygous for an x-linked trait will have a son with a genetic disorder if the genetic disorder is recessive?
The probability would be 0.5 or 50%. A heterozygous woman will pass on the X chromosome with the recessive allele to 50% of her sons, and since the disorder is recessive, the son would only have the disorder if the X chromosome with the recessive allele is inherited from the mother.
What are traits that are hidden called?
Recessive traits can be hidden if the organism inherits one dominant and one recessive allele (i.e. is heterozygous) for a gene. If a heterozygous organism mates with another heterozygous organism for the same trait, the recessive trait may be expressed in their offspring, which would mean that the offspring inherited two recessive alleles, one from each parent.
