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It depends.
If the child is male, the person to pass the trait on must be the mother. She may be a hybrid or color-blind herself for her to be capable of doing this. If the child is female, the father must be color-blind in addition to the mother being a carrier. Both have to donate the recessive gene to their daughter.
What else can I help you with?
What is the probability of color blindness if the father is color blind and the mother carries the trait?
All daughters are normal, half the sons are color blind. The above answer is incorrect. Half of the daughters are color blind and half of the sons are color blind. Since the father always donates color blindness, it is up to the mother in each case (in the son's case, the father is irrelevant) to determine if the child is color blind or not. Since she is a carrier, the chance is 50-50.
What is the risk of a colour blind child in a family when father is colour blind and mother is normal?
if the child is a boy, 0%. if it's a girl, either 100% if the trait is dominant in the father or 50% if it is recessive. there is also the possibilty of the daughter having it but just being a carrier (has the disease but no signs of it)
A color blind son inherited this trait from?
his mother because color blindness is a sex-linked trait that is found on the X chromosome, which is inherited from the mother, as opposed to the Y chromosome, which is inherited from the father. So a male can only inherit the gene for color blindness from his mom.
Red-green color blindness is an X-linked recessive trait A woman who has a color-blind mother and a father with normal color vision marries a?
man with normal color vision. Since the woman is a carrier of the red-green color blindness gene (inherited from her color-blind mother), there is a 50% chance that any son they have will be color-blind, as he would inherit the X chromosome with the color-blind gene from his mother. Daughters have a 50% chance of being carriers like their mother but will have normal color vision since they would inherit a normal X chromosome from their father.
Why cant women be color blind?
Women can be colour blind.AnswerI am a woman who is red--green colorblind. The trait is carried on the X chromosome. Males receive an X chromosome from their mother and a Y from their father. If the X carries the trait of colorblindness, the male will be colorblind. Females need to receive two defective X chromosomes to be colorblind, one from their father and one from their mother. If a women has only one defective X chromosome, she will be a carrier of the trait. My father was red-green colorblind and so was my mother's father, making my mother a carrier of the trait, although she is not colorblind herself. I have two sisters who are not colorblind, as they each received a non-defective X chromosome from my mother. I knew before my son was born that he would be red-green colorblind, as the X chromosome he received from me carried the trait.
Is color blind a dominant trait?
BLhah
Color-blindness is inherited as an X-linked recessive trait. A male who is color-blind marries a heterozygous woman. What percent of their total children will be color-blind?
In this scenario, the male with color-blindness has the genotype X^cY (where X^c represents the X chromosome with the color-blind trait). The heterozygous woman has the genotype X^cX (one normal vision X and one color-blind X). Their potential offspring can inherit either X^c or X from the mother and either X^c or Y from the father. This results in a 50% chance of having color-blind sons (X^cY) and a 50% chance of having daughters who are carriers (X^cX) but not color-blind. Therefore, 25% of their total children will be color-blind (only the sons can be color-blind in this case).
Which parental pair could produce female with color blindness?
X' = color blindnessX'X'-- X --X'Yis a cross that could lead to a color blind female as the mother is homozygous recessive and the father's X chromosome is the recessive color blind trait.
The family tree below shows the trait a colorblind The family tree below shows a trait a colorblindness. The only unknown is the father in the first generation what must be true about the father?
She has at least one recessive color blindness allele {apex}
What would the genotypes of parents have to be for them to have a color-blind daughter?
The daughter's father would have to have been colour blind, and the mother would need the inheritive gene from her father (the mother doesn't nessecarily need to show it, just have a colourblind father) in order for a female to end up actually colourblind. However, it's extremely rare.
If a color blind man has a color blind daughter then the mother has to be color blind as well?
The father has to be colorblind for the daughter to be colorblind because both X chromosomes must have the colorblindness gene in females because the colorblind gene is recessive. If only the mother is color deficient, then she merely passes on the gene to one of the X chromosomes in a female. If both the mother and father are both colorblind, then both X chromosomes in the female are effected and the female is colorblind. There are two scenarios in which a daughter may be born colorblind. 1. The father is colorblind and the mother is a carrier of the colorblind gene. The daughter will be either colorblind or a carrier of the colorblind gene. 2. The father and mother are both colorblind. If this is the case, then all of the children will be born colorblind.
Can a colorblind father and normal sighted homozygous mother produce a daughter that is a carrier?
Color blindness is an X-linked trait. That means it is carried in the X chromosome, which differentiates whether a baby will be a girl or a boy. Women have two X chromosomes (XX), and men have an XY combination. If a woman is a carrier for color blindness, only one of her chromosomes will be affected (we'll call it a little "x"), and for that reason she will not be colorblind. Men, on the other hand, only have one X chromosome, so any time they carry the colorblindness gene, they will be colorblind. A child inherits one chromosome from each parent. He/She will get an X chromosome from his/her mother, and an X from her father (if a girl) or a Y from his father (if a boy). So, If a woman is a carrier, Xx, and a man is normal, XY, they have several different chances for different offspring: XX (a normal girl) XY (a normal boy) Xx (a normal girl who carries the colorblindness gene) xY (a colorblind boy) The short answer is, that if a woman has a boy, he has a 50% chance of being colorblind.
