HH and Hh; Hh & Hh;Hh &hh; HH & hh
H is a dominant trait for the hair color red. The trait for white hair is recessiv.The parents genotypes are HH x hh.What will the genotype of the offspring be?
What are the possible genotypes if the offspring of the fathers HH for a trait and the mothers hh
The man could have either free hanging or attached earlobes. His possible genotypes could be either homozygous for free hanging earlobes (LL) or heterozygous for free hanging and attached earlobes (Ll).
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The term "hybrid" in biology means one who carries different alleles for the same trait. For example, a hybrid plant's genotype for height is Hh. When crossing two hybrids, we are performing this operation: Hh x Hh. The offsprings' genotypes can vary from: HH Hh hh
It's obvious from this problem that short hair is dominant in guinea pigs. In that case, if we have 25 out of 100 offspring that have long hair, then there is no doubt that the parents are heterozygous for short hair. If you use the punnet square, and hypothesize that both parents are heterozygous for short hair and long hair, you will get a 25% chance that the offspring will be long haired. So, the answer to this problem is that both parents are heterozygous. Let H = short hair and h = long hair. Hh dam x Hh sire gives us, according to the Punnet Square: 25% HH 50% Hh 25% hh
Heterozygote X HeterozygoteEg.Hh X Hh- produces HH, 2 Hh, hh = 3 different genotypesWhereas:HH X hh- produces all HhAnd HH X HH- produces all HH
Yes to the first one, no to the second one. Firstly, widow's peak is caused by a dominant gene while a straight hairline is caused by a recessive gene. Let 'H' be dominant and 'h' be recessive. So for a dominant gene, the trait still will be expressed whether the genotype of the person is homozygous dominant(HH) or heterozygous(Hh). For a recessive gene however, the trait will only be expressed when the genotype of the person is homozygous recessive (hh). So two people with a widow's peak CAN have a child with a stright hairline, provided both of their genotypes are Hh. This is because by crossing their genotypes, they can have a possibility of having child with the genotype HH(widow's peak), Hh(widow's peak), and also hh(straight hairline). The ratio of these three possibilities however, are 1:2:1. So the odds of having a child with a straight hairline in this case is 1:3. If the two people who have widow's peak have the genotype HH or one of them HH and the other Hh, then the possibility of having a child with a straight hairline is 0. This is because by crossing their genotypes together, the genotype of the child will either be HH for the first case, and HH or Hh for the second case. For two people who have a straight hairline, the genotype of both will definitely be homozygous recessive (hh), thus child will definitely have the recessive gene. Therefore, it is not possible for two people with straight hairline to have a child with widow's peak.
Make a punnett square! 50% Hh 50% hh
Yes - Hh is heterozygous. HH is homozygous, and hh is homozygous.
it is because the parents each were heterozyous dominant. meaning each of them had a dominant allele and a recessive allele. the dominant allele would be the curly hair, and the recessive allele would be the straight hair. There would be a 1/4 chance that the child would have curly hair, and a 3/4 chance that they would have curly hair. Say that the Curly hair allele was H and the straight hair allele was h. In order for the parents to have curly hair, they would either have to have an HH gamete or an Hh gamete. Seeing as though the child came out with curley hair, both parents would have to have an Hh gamete. In order to find out the probability, you multiply the parents gametes. (Hh)(Hh). This will give you HH, Hh, Hh, hh. seeing has three of the gametes have the dominant allele, this child will have curly hair, and one is a homozygous recessive, so it will turn out with straight hair.