The probability of a child being color blind depends on the parents' genetic makeup. If the mother is a carrier of the color blindness gene located on the X chromosome and the father does not carry the gene, the chances are 0% for a daughter and 50% for a son to inherit color blindness. If the father is color blind and the mother is a carrier, the chances are 50% for a daughter and 50% for a son to inherit color blindness.
All daughters are normal, half the sons are color blind. The above answer is incorrect. Half of the daughters are color blind and half of the sons are color blind. Since the father always donates color blindness, it is up to the mother in each case (in the son's case, the father is irrelevant) to determine if the child is color blind or not. Since she is a carrier, the chance is 50-50.
If the parent went blind due to an accident or a birth defect (born blind) then no. But if the parent has a disease that caused them to go blind then it is possible to inherit that as a child.
A child may be color blind if they have difficulty distinguishing certain colors or shades. They may also exhibit specific behaviors like difficulties matching colors, confusing colors, or describing colors differently than others. If you suspect your child may be color blind, it's best to consult with an eye care professional for a formal evaluation.
man with normal color vision. Since the woman is a carrier of the red-green color blindness gene (inherited from her color-blind mother), there is a 50% chance that any son they have will be color-blind, as he would inherit the X chromosome with the color-blind gene from his mother. Daughters have a 50% chance of being carriers like their mother but will have normal color vision since they would inherit a normal X chromosome from their father.
NOW. Colourblindness we will assume, is a Sex-Linked Disorder. Hence, the sex chromosomes are involved in determinig the phenotypes of the children. XY --male XX--female XbY--colourblind male XBXb --normal female Cross: (parents) Xby * XBXb F1 progeny/offspring XBXb, XbXb, XBY, XbY 50 % of the children will be colourblind. This is a very simple question. You also need to clarify within the question if it is sex linked or autosomal.
Blind Chance was created in 1981.
if the child is a boy, 0%. if it's a girl, either 100% if the trait is dominant in the father or 50% if it is recessive. there is also the possibilty of the daughter having it but just being a carrier (has the disease but no signs of it)
The duration of Blind Chance is 2.03 hours.
It depends. If the child is male, the person to pass the trait on must be the mother. She may be a hybrid or color-blind herself for her to be capable of doing this. If the child is female, the father must be color-blind in addition to the mother being a carrier. Both have to donate the recessive gene to their daughter.
The expected phenotypic ratio for their offspring is 1:1, with a 50% chance of being color blind (male with the X-linked recessive trait) and a 50% chance of having normal color vision. This is because the daughter is a carrier of the recessive allele, which can be passed on to her offspring regardless of the father's color vision status.
Women can not be colorblind, only men. For questions like these a punnett square is useful. Men can not carry the colorblind trait, but women can. I know this is kind of confusing. When a carrier ( a woman with the color blind trait) has children with a man ( color blind or not) her kids will have 50% chance of having that trait. If its a girl, she will be the carrier. If its a boy, he will have the colorblind trait. SO TO ANSWER YOUR QUESTION: Theoreticaly, 1 of the daughters will be the carrier, and the son will have a 50% chance of being colorblind. Women can be colorblind, its just rare. About every 6400 women one is colour blind and with men, every 80 men 1 is colour blind.