The bulb won't work.
the wires to the bulb is one reason among others. the wires to the bulb is one reason among others.
If someone only connect one of the wires to the bulb holder, the circuit will be open and the lamp will not light. This is the same principal that a switch in the circuit does. It opens and closes the circuit.
Nothing much will happen except the same bulb will not blow..
it would be ok in a circuit which didn't need a light bulb.
if the copper wire (s) were conneting the battery to the lamp removing one of the wires would break a circut and the lamp goes out.
Nothing would happen.
No. Or at least not perceptually. The wires only supply electricity to the bulb - the bulb is what limits the current.
by shorter wires or thiker wires
The glass of the light bulb is not conductive, so the circuit would not be completed. You would need to join the wires to the positive and negative contacts on the base of the bulb for the circuit to work.
The tiny wires in a light bulb are called filament wires. They are made of tungsten and are responsible for emitting light when an electric current passes through them.
I would check your grounds at the bulb wires. Usually, the bulb wires are grounded (or bulb bracket). Sounds like a grounding problem somewhere.
It is dependant on whether the switches are in wired in a parallel or series configuration. If the switches are wires in parallel then both switches would have to be off to turn the light bulb off. Either switch could turn the light bulb on. If the switches are wired in series then both switches would have to be on to turn the light bulb on. Either switch could turn the light bulb off.