nominal stress is the engineering stress, which is the force divided by the original Area. true stress is the force divided by the area of the deformed specimen as it deforms. Since the area of the deformed specimen is usually smaller than the original area true stress is higher than the nominal stress... Ali D
direct stress is based on the value obtained by dividing the load by originalcross-sectional area. That is the reason why the value of stress started dropping after neck is formedin mild steel (or any ductile material).But actually as material is stressed itscross-sectional area changes. We should divide load by the actual cross-sectional area to get truestress in the material. To distinguish between the two values we introduce the terms nominal stress and true stress True Stress =Load/ActualCross-sectionalArea Nominal Stress =Load/Original Cross-sectionalArea
see the following questionWhat_the_difference_between_true_strain_and_engineering_strain
it is the nominal size?
No. Nominal interest rate is the rate before adjustments for inflation.
Fracture stress is only less than ultimate tensile strength in an engineering stress-strain diagram. This is because the material will experience a maximum stress before it undergoes necking. After necking, stress will decrease again until the material snaps.
The difference between true stress & engineering stress is summarised as follows: Engineering stress assumes that the area a force is acting upon remains constant, true stress takes into account the variation in the cross sectional area as a result of the stress induced deformation (strain) of a material. For example a steel bar in tension once its yield point or stress is reached will start to "neck". Necking is the localized concentration of strain in a small region of the material, causing a reduction in cross sectional area at this point. To calculate the engineering stress in the above case, the applied load is divided by the original cross sectional area, however the true stress would be equal to the load divided by the new deformed cross sectional area. Therefore true stress is likely to be significantly higher than engineering stress. Note that while the material is deforming elastically before the yield point is reached there will be some difference between true and engineering stress (as the material is changing shape) but it will be much smaller than the difference after the yield point is reached. A rock core in a uni-axial compression test will typically expand radially under loading. Therefore in this case, the engineering stress (based on the original diameter) will be larger than the true stress within the material.
that is TRUE
true
true
Yes, generally speaking, an interviewer is likely to obtain a higher response rate than a printed survey form. This is because the interviewer can build rapport, clarify any doubts, and encourage participation through personal interaction, which can increase the respondent's willingness to participate.
Yes, it is true.
yes