The equation of an ellipse is
((x-x0)^2)/b^2)+((y-y0)^2/a^2)=1
hope that helps! : )
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that equation is for an ellipse, true, but that's not what is needed here.
In this case you can just use Kepler's 3rd law which is: p^2=a^3
Which means the period (in years) squared is equal to the radius (or semi major axis) in AU cubed.
Uranus.
horizontal
have 3 major axis power germany,italy,and japan were part of a miltary,alliance
The axis just defines their rotation. It is relative to spin, so if a body does not spin, it has no axis. Kind of an imaginary line, like the equator. It is used for reference. Also an object that is not round and symmetrical and has a length and a width can also be referenced by these dimensions. The Longitudinal axis is usually an axis through the longest dimension of the body.
Japan.
Orbital information. You need to know the size of the "semi-major axis". Then you can calculate the orbital period, using Kepler's Third Law.
To calculate the orbital period using the semi-major axis, you can use Kepler's third law of planetary motion. The formula is T2 (42 / G(M1 M2)) a3, where T is the orbital period in seconds, G is the gravitational constant, M1 and M2 are the masses of the two objects in the orbit, and a is the semi-major axis of the orbit. Simply plug in the values for G, M1, M2, and a to find the orbital period.
Major axis of mentioned comet has length of 8 AU (1 AU at perihelion plus 7 AU at apohelion on the opposite side of Sun). According to Kepler's third law, the square of orbital period is directly proportional to cube of the orbit's major axis. When using astronomical units for distance and sidereal years for time, this simplifies to: T2 = a3, where T - orbital period a - length of major axis We can then calculate that T for a = 8 AU is about 22.62 years.
The axis of Pluto is tilted at an angle of approximately 119.5 degrees in relation to its orbital plane around the Sun. This extreme tilt contributes to the significant variations in seasons experienced on Pluto as it orbits the Sun.
In Kepler's first law, the semi-major axis refers to the longest radius of an elliptical orbit, which extends from the center of the ellipse to its outer edge. The major axis is the full length of this longest diameter, passing through both foci of the ellipse. Essentially, the semi-major axis is half the length of the major axis, defining the size of the orbit and influencing the orbital period of the celestial body.
The Axial tilt of the dwarf planet Ceres is about 3°
Not at all. The only thing that sets the orbital period is the semimajor axis, which is the average of the maximum and minimum distances from the Sun.
The semi-major axis.
Yes, all 8 planets along with planetesimals like Pluto revolve around and axis.
The planets rotation does not really relate to the orbital period. Some planets like Mercury and Venus and Mars orbit the sun in a short time, but take a long time to rotate on their axis, Earth is the exception, where a collision with the moon many years ago may have caused its days to be a lot shorter than the other rocky planets. Saturn and Jupiter rotate fairly quickly on their axis.
Unlike the other planets, Uranus' axis of rotation is almost parallel to its orbital plain. All the other planets' axis of rotation are almost perpendicular to their orbital planes.So most planets can be visualized as spinning like tops on a table, where the table is the plane of their orbits. Uranus would be visualized as rolling on its side as it moves around its orbit.it spins sidewaysIt spins sideway.
The average distance from the sun to a planet is its semi-major axis, which is the longest radius of its elliptical orbit.