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The equation of an ellipse is
((x-x0)^2)/b^2)+((y-y0)^2/a^2)=1
hope that helps! : )
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that equation is for an ellipse, true, but that's not what is needed here.
In this case you can just use Kepler's 3rd law which is: p^2=a^3
Which means the period (in years) squared is equal to the radius (or semi major axis) in AU cubed.
What else can I help you with?
Which planet's axis is tilted almost 90 degrees to its orbital plain?
Uranus.
When the denominator of the x2-term is greater than that of the y2-term the major axis is the axis?
horizontal
What is axis power?
have 3 major axis power germany,italy,and japan were part of a miltary,alliance
Why do planets have axis?
The axis just defines their rotation. It is relative to spin, so if a body does not spin, it has no axis. Kind of an imaginary line, like the equator. It is used for reference. Also an object that is not round and symmetrical and has a length and a width can also be referenced by these dimensions. The Longitudinal axis is usually an axis through the longest dimension of the body.
What was the major axis power in the Pacific in World War 2?
Japan.
What must you know in order to find out a planets period of revolution?
Orbital information. You need to know the size of the "semi-major axis". Then you can calculate the orbital period, using Kepler's Third Law.
How can one calculate the orbital period using the semi-major axis?
To calculate the orbital period using the semi-major axis, you can use Kepler's third law of planetary motion. The formula is T2 (42 / G(M1 M2)) a3, where T is the orbital period in seconds, G is the gravitational constant, M1 and M2 are the masses of the two objects in the orbit, and a is the semi-major axis of the orbit. Simply plug in the values for G, M1, M2, and a to find the orbital period.
According to Kepler's third law what is the square of the planets period in years?
According to Kepler's third law, the square of a planet's orbital period (T) in years is directly proportional to the cube of the semi-major axis (a) of its orbit in astronomical units (AU). Mathematically, this is expressed as (T^2 \propto a^3). In simpler terms, if you know the semi-major axis of a planet's orbit, you can determine its orbital period by taking the cube root of the semi-major axis and squaring it. This law highlights the relationship between the distance of planets from the Sun and their orbital periods.
A comet moves in an elliptical orbit around the sun its distance from the sun varies between 1 AU and 7 AU Calculate its orbital period?
Major axis of mentioned comet has length of 8 AU (1 AU at perihelion plus 7 AU at apohelion on the opposite side of Sun). According to Kepler's third law, the square of orbital period is directly proportional to cube of the orbit's major axis. When using astronomical units for distance and sidereal years for time, this simplifies to: T2 = a3, where T - orbital period a - length of major axis We can then calculate that T for a = 8 AU is about 22.62 years.
What is the axis tilt on Pluto?
The axis of Pluto is tilted at an angle of approximately 119.5 degrees in relation to its orbital plane around the Sun. This extreme tilt contributes to the significant variations in seasons experienced on Pluto as it orbits the Sun.
What is Ceres's axis tilt?
The Axial tilt of the dwarf planet Ceres is about 3°
What are the major axis in the semi major axis of the orbital shape express in Kepler's first law?
In Kepler's first law, the semi-major axis refers to the longest radius of an elliptical orbit, which extends from the center of the ellipse to its outer edge. The major axis is the full length of this longest diameter, passing through both foci of the ellipse. Essentially, the semi-major axis is half the length of the major axis, defining the size of the orbit and influencing the orbital period of the celestial body.
What is law of periods?
The law of periods, also known as Kepler's third law of planetary motion, states that the square of the orbital period of a planet (the time it takes to complete one orbit around the sun) is directly proportional to the cube of the semi-major axis of its orbit (the average distance from the sun). Mathematically, it can be expressed as ( T^2 \propto a^3 ), where ( T ) is the orbital period and ( a ) is the semi-major axis. This law highlights the relationship between the distance of planets from the sun and their orbital speeds, showing that planets further from the sun take longer to complete their orbits.
How does a planets mass effect its orbital period according to Kepler?
Not at all. The only thing that sets the orbital period is the semimajor axis, which is the average of the maximum and minimum distances from the Sun.
A planet average distance from the sun is also What part of the orbital ellipse?
The semi-major axis.
Do all eight planets have an axis?
Yes, all 8 planets along with planetesimals like Pluto revolve around and axis.
How does a planets revolution relate to orbital period?
The planets rotation does not really relate to the orbital period. Some planets like Mercury and Venus and Mars orbit the sun in a short time, but take a long time to rotate on their axis, Earth is the exception, where a collision with the moon many years ago may have caused its days to be a lot shorter than the other rocky planets. Saturn and Jupiter rotate fairly quickly on their axis.
