If a quadratic function has the points (-4,0) and (14,0), what is equation of the axis of symmetry?
The term "pyramid" denotes a solid with a polygonal base and triangular sides (all converging at the same point. As such is does not have to have any axis of symmetry. There are pyramids that do have an axis of symmetry and ones with planes of symmetry.
The quadratic formula is famous mainly because it allows you to find the root of any quadratic polynomial, whether the roots are real or complex. The quadratic formula has widespread applications in different fields of math, as well as physics.
Fourfold rotational. In chemistry, it would be called a C4 axis.
In mathematics, the relationship between x and y is often represented by an equation or a function. This relationship shows how the value of y changes based on the value of x. It can be linear, quadratic, exponential, or any other type of relationship depending on the specific equation or function being used.
The equation of an ellipse is ((x-x0)^2)/b^2)+((y-y0)^2/a^2)=1 hope that helps! : ) ____________________________________________________ that equation is for an ellipse, true, but that's not what is needed here. In this case you can just use Kepler's 3rd law which is: p^2=a^3 Which means the period (in years) squared is equal to the radius (or semi major axis) in AU cubed.
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Yes and this will happen when the discriminant of a quadratic equation is less than zero meaning it has no real roots.
First the formula is g(x)=ax2+bx+c First find where the parabola cuts the x axis Then find the equation of the axis of symmetry Then
It is x = +/- 2 depending on whether the second term in the equation is -12x or +12x.
It is the axis of symmetry.
Your equation must be in y=ax^2+bx+c form Then the equation is x= -b/2a That is how you find the axis of symmetry
To find the axis of symmetry for the quadratic equation ( y = -x^2 + 2x - 4 ), you can use the formula ( x = -\frac{b}{2a} ), where ( a ) and ( b ) are the coefficients from the equation in standard form ( y = ax^2 + bx + c ). Here, ( a = -1 ) and ( b = 2 ). Plugging in the values, the axis of symmetry is ( x = -\frac{2}{2 \times -1} = 1 ). Thus, the axis of symmetry is ( x = 1 ).
Complete the square, then find the value of x that would make the bracket zero ax^2 + bx + c = 0 line of symmetry is x = (-b/2a)
The axis of symmetry of a quadratic function in the form (y = ax^2 + bx + c) can be found using the formula (x = -\frac{b}{2a}). This vertical line divides the parabola into two mirror-image halves. To find the corresponding (y)-coordinate, substitute the axis of symmetry value back into the quadratic function.
There is no equation (nor inequality) in the question so there can be no graph - with or without an axis of symmetry.
It is y = -b/(2a)
It is a turning point. It lies on the axis of symmetry.