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Metalization in sponge iron is calculated by measuring the percentage of iron content in the sponge iron compared to the total iron oxides present in the feed material. The formula used is:

[ \text{Metalization (%)} = \left( \frac{\text{Weight of metallic iron in sponge iron}}{\text{Weight of total iron oxides in the feed}} \right) \times 100 ]

For example, if you start with 100 kg of iron ore containing 70 kg of iron oxides, and the produced sponge iron contains 55 kg of metallic iron, the metalization would be:

[ \text{Metalization} = \left( \frac{55 , \text{kg}}{70 , \text{kg}} \right) \times 100 \approx 78.57% ]

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How do you calculate sponge iron metalization?

It is the ratio of metallic iron to the total iron ,convert in percentage


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To calculate total iron in sponge iron when the metallic iron content is known, you can use the formula: Total Iron = Metallic Iron × (1 + Iron Oxide Ratio). The iron oxide ratio reflects the proportion of iron present in the form of oxides, which can vary based on the production process. For example, if you have 90% metallic iron and an oxide ratio of 0.1, the total iron would be calculated as 90% × (1 + 0.1) = 99%.


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