answersLogoWhite

0

Accelerate at a constant rate (although if the net force is zero, this constant acceleration would be zero, so it wouldn't really be proper to say its accelerating in that case).

User Avatar

Wiki User

15y ago

What else can I help you with?

Related Questions

What is the net force on a crate sliding at an unchanging speed when pushed with a steady force of 75 N?

The net force on the crate sliding at a constant speed is zero. This is because the applied force of 75 N is balanced by the frictional force opposing the motion. As a result, the crate does not accelerate, and the net force is zero.


What is the net force when encounters 15 N air resistance?

The net force would be the difference between the applied force and the air resistance. If the applied force is greater than the air resistance, then the net force would be in the direction of the applied force. If the air resistance is greater than the applied force, then the net force would be in the opposite direction.


What is the difference between the terms force and net force?

nothing-------------------------------------------------------------------------Rafaelrz.Suppose a given body is subject to different forces, F1, F2, F3, . . .,then the net force FN applied to the body is that which is equivalentto sum of all the forces Fi,acting on the body.


What if your body applies force to the ground as weight. If you weigh 450 newtons and carry a backpack that weighs 45 newtons what is the net force applied downward to the ground?

495 n


When a force equals its weight is applied on a body what is its acceleration?

The acceleration depends on the net force. So, you must add the forces together as vectors. The result in this case depends in what direction the force is applied.


When a body moves with constant velocity what is the magnitude of net force is the magnitude of force applied to keep the body moving equal to less than or more than frictional force explain?

When a body moves with constant velocity, the net force acting on it is zero as there is no acceleration. The magnitude of the force applied to keep the body moving is equal to the frictional force opposing its motion. This ensures that the forces are balanced, resulting in a constant velocity without any acceleration.


In symbols when the applied force force applied -(blank) then Net (blank) and the object will travel with a constant (blank)?

In symbols, when the applied force ( F_{\text{applied}} ) is equal to the frictional force ( F_{\text{friction}} ), then the net force ( F_{\text{net}} ) is zero, and the object will travel with a constant velocity. This means that there is no acceleration, and the object maintains its state of motion.


When the force applied to an object produce a net force of zero the forces are?

Balanced


What if your body applies force to the ground as weight. If you weigh 450 newtons and carry a backpack that weighs W newtons what is the net force applied downward to the ground?

The net force applied downward to the ground is 450 newtons + W newtons. When standing still (not accelerating), the net force must be zero according to Newton's first law. This means the force pushing down must be balanced by the force pushing up (from the ground).


What is Newton's second law of motion-?

The net force on an object is equal to the mass of the object multiplied by its acceleration.The second law of motion states that:FORCE=MASS*ACCELERATIONA body of mass m subject to a net force F undergoes an acceleration a that has the same direction as the force and a magnitude that is directly proportional to the force and inversely proportional to the mass, i.e., F = ma. Alternatively, the total force applied on a body is equal to the time derivative of linear momentum of the body.


Can you have a net force when the forces applied to the objects are balanced?

Yes, you will have a net force but its magnitude is zero if it does not cause any acceleration.


Is the net force dependent on tension?

Net force depend on all forces applied to an object you are considering in your experiment/problem.