this is false. the horizontal speed of the object has absolutely nothing to do with how long it takes to fall. if you fire a bullet on level ground it will hit the ground at the same time an apple would if you drop it from the same distance above the ground at the same time. the force of gravity is the same on everything on earth.
A projectile has maximum horizontal range when it is launched at an angle of 45 degrees to the horizontal. This angle allows for the ideal balance between the horizontal and vertical components of the projectile's velocity, ensuring that it travels the farthest distance before hitting the ground.
If the non-horizontal projectile is launched abovehorizontal, thenit's the second one to hit the ground, after the horizontal one.If the non-horizontal one is launched below horizontal, then it'sthe first to hit the ground, before the horizontal one.
A half projectile refers to the projectile motion of an object where it is launched at an angle of 45 degrees to the horizontal. This angle maximizes the range of the projectile for a given initial velocity, making it travel the furthest distance before hitting the ground. The path of the projectile is a parabolic curve.
initial velocity, angle of launch, height above ground When a projectile is launched you can calculate how far it travels horizontally if you know the height above ground it was launched from, initial velocity and the angle it was launched at. 1) Determine how long it will be in the air based on how far it has to fall (this is why you need the height above ground). 2) Use your initial velocity to determine the horizontal component of velocity 3) distance travelled horizontally = time in air (part 1) x horizontal velocity (part 2)
For the projectile to land at the same distance with the same initial speed, it must be launched at an angle of 15 degrees from the horizontal. This is because the range of a projectile is maximized when launched at a 45-degree angle. So, launching at 15 degrees in the opposite direction of 75 degrees should bring the projectile to the same landing point.
-- the initial horizontal speed of the projectile -- the time it remains in flight before it hits the ground
initial velocity, angle of launch, height above ground When a projectile is launched you can calculate how far it travels horizontally if you know the height above ground it was launched from, initial velocity and the angle it was launched at. 1) Determine how long it will be in the air based on how far it has to fall (this is why you need the height above ground). 2) Use your initial velocity to determine the horizontal component of velocity 3) distance travelled horizontally = time in air (part 1) x horizontal velocity (part 2)
Range of a projectileThe path of this projectile launched from a height y0 has a range d.In physics, a projectile launched with specific initial conditions in a uniform gravity field will have a predictable range. As in Trajectory of a projectile, we will use:g: the gravitational acceleration-usually taken to be 9.80 m/s2 (32 f/s2) near the Earth's surfaceθ: the angle at which the projectile is launchedv: the velocity at which the projectile is launchedy0: the initial height of the projectiled: the total horizontal distance travelled by the projectileWhen neglecting air resistance, the range of a projectile will beIf (y0) is taken to be zero, meaning the object is being launched on flat ground, the range of the projectile will then simplify toso to increase the range θ shoud vary from 0 to 45 and after 45 it starts decreasing.
The two components of a projectile are the horizontal component, which determines the distance the projectile travels, and the vertical component, which influences the projectile's height and the time it takes to reach the highest point and return to the ground.
A motion thrown at an angle is called projectile motion. It involves an object being launched at an angle relative to the ground and following a curved path due to the combination of its horizontal and vertical velocities.
The range of a projectile on level ground, when air resistance is ignored, isd = v2*sin(2x)/g wherev is the intial velocity of the projectile,x is the angle above the horizontal at which the projectile is launchedandg is the acceleration due to the earth's gravity.This function is a maximum when x = 45 degrees and so d is smaller for other values of x.The range of a projectile on level ground, when air resistance is ignored, isd = v2*sin(2x)/g wherev is the intial velocity of the projectile,x is the angle above the horizontal at which the projectile is launchedandg is the acceleration due to the earth's gravity.This function is a maximum when x = 45 degrees and so d is smaller for other values of x.The range of a projectile on level ground, when air resistance is ignored, isd = v2*sin(2x)/g wherev is the intial velocity of the projectile,x is the angle above the horizontal at which the projectile is launchedandg is the acceleration due to the earth's gravity.This function is a maximum when x = 45 degrees and so d is smaller for other values of x.The range of a projectile on level ground, when air resistance is ignored, isd = v2*sin(2x)/g wherev is the intial velocity of the projectile,x is the angle above the horizontal at which the projectile is launchedandg is the acceleration due to the earth's gravity.This function is a maximum when x = 45 degrees and so d is smaller for other values of x.
The forces acting on a projectile are gravity, which causes it to fall towards the ground, and air resistance, which opposes its motion through the air. Additionally, the initial velocity at which the projectile is launched also influences its trajectory.