Vrms=sqaure root(3kT/m)
To conver Vrms in to Voltage Source we useVm=√2 (vi)
To convert from Vrms (voltage root mean square) to Vac (voltage alternating current peak), you can use the formula: Vac = Vrms × √2. For 56.56 Vrms, the calculation would be: 56.56 × √2 ≈ 80.00 Vac. Thus, 56.56 Vrms is approximately 80.00 Vac.
VRMS = 1/N times square root of [ sum(Vn2) ]
Vrms=Vm/1.414................... from this u can find Vm.....magnitude of voltage.
Approx. 280 VRMS. Vpeak * 0.707 = Vrms
Many can measure both - Vrms (AC) or DC voltage.
Vrms = Vpp/squareroot(2)This can be written another way:Vrms * squareroot(2) = VppAnswerThe question asks for the relationship between the rms value of voltage, and the peak-to-peak value of voltage, not the peak value (Vmax) of voltage, so:Vp-p = 2 Vmax = 2(1.414) Vrms = 2.828 Vrms
Actually ,Vrms is the root mean square voltage for example, consider voltages 5V,10V,2V So Vrms is the root value of {[(5*5)+(10*10)+(2*2)]/3} And Vpeak is 10V Thanks!!!!!(Zayed)
238
Vp=2 Vdc=50 r=Vrms/Vdc Vrms=Vp/1.121 so r=0.028
KVA is an acronym for killo volt - amperes. It is a measure of power (both real and reactive) defined as P = Vrms * Irms. If there is a power factor associated with this, it can be used to separate the real and reactive power:P(real) = Vrms * Irms * pfP(reactive) = Vrms * Irms * (1 - pf)
The root mean square velocity of atoms in a gas can be calculated using the formula: vrms = sqrt((3kT)/m), where k is the Boltzmann constant, T is the temperature in Kelvin, and m is the molar mass of the gas. For neon with a molar mass of 20.18 g/mol, the vrms at 308 K would be approximately 516 m/s.