The word "audio" has 5 letters and 3 vowels.
There are five vowels in the word "sequoia."
The word "onomatopoeia" has 11 letters, with 6 vowels and 5 consonants. Therefore, there are 11!/(6!5!) = 33,120 ways to arrange the word "onomatopoeia".
"Ocean" fits the criteria of being a 5-letter word with 2 consonants (c and n) and 3 vowels (o, e, a).
"Elephant" is a word that contains 2 vowels (e, a) and 5 consonants (l, p, h, n, t).
five to twenty one
Uncommon
Koala
Rocking is a word with 7 letters 5 consonants and 2 vowels
The ratio is 4:5.
agree
In the word DAUGHTER, there are 3 vowels namely, A, U, and E, and 5 consonants namely, D, G, H, T, and R. Number of ways of selecting 2 vowels out of 3 vowels = Number of ways of selecting 3 consonants out of 5 consonants = Therefore, number of combinations of 2 vowels and 3 consonants = 3 × 10 = 30 Each of these 30 combinations of 2 vowels and 3 consonants can be arranged among themselves in 5! ways. Hence, required number of different words = 30 × 5! = 3600
peace, every
Alligator has nine letters, but the word only has four vowels.
The word "IMAGINARY" has 9 letters, including 4 vowels (I, A, I, A) and 5 consonants (M, G, N, R, Y). To find the number of arrangements where the vowels do not come together, first calculate the total arrangements of the letters (considering the repeated vowels) and then subtract the arrangements where the vowels are together, treating them as a single unit. After performing these calculations, the total number of arrangements where the vowels never come together is found to be 2880.
There are five vowels in the word "sequoia."
Can it only consist of vowels? Many words have 5 vowels. Queueing has five in a row.
12 Letters. 7 consonants and 5 vowels.