Both parents are Dd. They express the dominant gene but carry the recessive one, so there's a 25% chance that the pup will express the recessive one. If either parent was DD, then it would be impossible to produce a pup that expresses the recessive gene.
They will produce gametes that are also homozygous.
The offspring in the first column both have two dominant T alleles. Therefore, you know that the father (parent on the left hand side) is TT and the mother (parent on the top) has a dominant T in that column too. The offspring in the second column are Tt. The dominant T came from the father, as figured out in the first part of the problem. The recessive allele t came from mother's second empty box.
If the parent generation consisted of a homozygous dominant parent and a homozygous recessive parent, then the F1 generation would be 100% heterozygous.
Two types: A heterozygous parent (Aa) and a homoygous recessive parent (aa) can produce phenotypically dominate and phenotpically recessive offspring (with 50% genotypes Aa and the other 50% aa). If the genes are co-dominate then the offspring can have blended traits and recessive traits phenotypically.
dominant parent traits.
dominant parent traits.
Rr
Well, it really depends. You have to look at their pedigree and find out if anyone in their family has long hair. Such as the grandpa or grandma. 2 short hair dachsunds had 4 puppies. 3 were short haired and one was long. Their next litter was 2:2 and their last litter was 2:2 again. The dads parents both had long hair.
Let Y represent the dominant allele, and yrepresent the recessive allele. Let us also assume that "pure" means homozygous for that trait ("pure' is not the usual term for this, "homozygous" is) So, the two genotypes of the parents of the cross are: Parent 1: YY Parent 2: yy To solve a problem like this, one always has to determine what kind(s) of gametes each parent can produce. Both parents are homozygous for their respective traits, so in this case, each parent can only produce one kind of gamete: Parent 1 can only produce Ygametes, and Parent 2 can only produce y gametes. Therefore, every one of their offspring will have the following genotype: Yy Since every one of the offspring of the cross carries a Y allele, and Y is dominant, all of the offspring will be yellow.
HH and Hh; Hh & Hh;Hh &hh; HH & hh
RR X rr 100% Rr Heterozygous resistant for poison ivy.
No, there are more than two possible genotypes among the offspring when both parent genotypes are Aa. The potential genotypes for the offspring are AA, Aa, and aa, resulting in a total of three different genotypes. The expected ratio from a Punnett square for this cross is 1 AA : 2 Aa : 1 aa.