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A caricature.
The same. 0.233 moles C (1mol C/1mo CO2 ) = 0.233 moles of Carbon.
2.6 moles (12.01 g C/1 mol C) = 31.226 grams of C
The combustion of butane (C₄H₁₀) can be represented by the balanced equation: 2 C₄H₁₀ + 13 O₂ → 8 CO₂ + 10 H₂O. From this equation, we see that 2 moles of butane produce 8 moles of carbon dioxide. Therefore, if 5.31 moles of C₄H₁₀ are used, the moles of CO₂ produced can be calculated as follows: (5.31 moles C₄H₁₀) × (8 moles CO₂ / 2 moles C₄H₁₀) = 21.24 moles of CO₂.
Oliver C. Moles has written: 'Student Discipline Strategies'
The balanced chemical equation is ( 5C(s) + 2SO_2(g) \rightarrow CS_2(l) + 4CO(g) ). According to the stoichiometry of the reaction, 5 moles of carbon (C) react with 2 moles of sulfur dioxide (SO₂). To find the moles of C needed for 0.480 moles of SO₂, use the ratio ( \frac{5 , \text{moles C}}{2 , \text{moles SO}_2} ). Therefore, the moles of C required are ( 0.480 , \text{moles SO}_2 \times \frac{5 , \text{moles C}}{2 , \text{moles SO}_2} = 1.20 , \text{moles C} ).
Choral group, chicken gumbo, crab grass meet that description. Church group is another.
The answer is 2,17 moles carbon.
How many moles of C are needed to react with 0.490 mole SO2?