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The same. 0.233 moles C (1mol C/1mo CO2 ) = 0.233 moles of Carbon.
2.6 moles (12.01 g C/1 mol C) = 31.226 grams of C
The combustion of butane (C₄H₁₀) can be represented by the balanced equation: 2 C₄H₁₀ + 13 O₂ → 8 CO₂ + 10 H₂O. From this equation, we see that 2 moles of butane produce 8 moles of carbon dioxide. Therefore, if 5.31 moles of C₄H₁₀ are used, the moles of CO₂ produced can be calculated as follows: (5.31 moles C₄H₁₀) × (8 moles CO₂ / 2 moles C₄H₁₀) = 21.24 moles of CO₂.
To find the number of moles of carbon (C) in 0.733 moles of C17H21NO, first identify the number of carbon atoms in one molecule of C17H21NO, which is 17. Therefore, the number of moles of carbon can be calculated by multiplying the number of moles of the compound by the number of carbon atoms: 0.733 moles of C17H21NO × 17 moles of C/mole of C17H21NO = 12.441 moles of C. Thus, there are approximately 12.44 moles of carbon present.
The balanced chemical equation is ( 5C(s) + 2SO_2(g) \rightarrow CS_2(l) + 4CO(g) ). According to the stoichiometry of the reaction, 5 moles of carbon (C) react with 2 moles of sulfur dioxide (SO₂). To find the moles of C needed for 0.480 moles of SO₂, use the ratio ( \frac{5 , \text{moles C}}{2 , \text{moles SO}_2} ). Therefore, the moles of C required are ( 0.480 , \text{moles SO}_2 \times \frac{5 , \text{moles C}}{2 , \text{moles SO}_2} = 1.20 , \text{moles C} ).
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Choral group, chicken gumbo, crab grass meet that description. Church group is another.
The answer is 2,17 moles carbon.