2.6 moles (12.01 g C/1 mol C) = 31.226 grams of C
To find the number of moles of carbon (C), you need to divide the given mass by the molar mass of carbon. The molar mass of carbon is approximately 12.01 g/mol. Therefore, 0.170 g of carbon is equal to 0.170 g / 12.01 g/mol = 0.014 moles of carbon.
To find the number of moles of carbon (C) in 32.6 g of ethane (C2H6), first calculate the molar mass of C2H6, which is approximately 30.07 g/mol. Since each molecule of C2H6 contains 2 moles of carbon, the total number of moles of C in 32.6 g of C2H6 can be found by dividing the mass by the molar mass and then multiplying by 2. This gives: [ \text{Moles of C} = \left(\frac{32.6 , \text{g}}{30.07 , \text{g/mol}}\right) \times 2 \approx 2.16 , \text{moles of C}. ]
When 4,000 grams of acetylene (C₂H₂) burns completely, it reacts with oxygen to produce carbon dioxide (CO₂) and water (H₂O). The balanced equation for the combustion of acetylene is: 2 C₂H₂ + 5 O₂ → 4 CO₂ + 2 H₂O. The molar mass of C₂H₂ is approximately 26 g/mol, so 4,000 g corresponds to about 153.85 moles of C₂H₂. From the equation, 2 moles of C₂H₂ produce 4 moles of CO₂, meaning 153.85 moles of C₂H₂ will produce 307.7 moles of CO₂. Therefore, the total mass of CO₂ produced is approximately 13,511 grams (or 13.5 kg).
To find the mass of 2.00 moles of acetylene (C₂H₂), first calculate the molar mass. The molar mass of C₂H₂ is approximately 26.04 g/mol (12.01 g/mol for carbon and 1.01 g/mol for hydrogen). Therefore, the mass in grams is calculated as follows: 2.00 moles × 26.04 g/mol = 52.08 grams. Thus, there are 52.08 grams in 2.00 moles of acetylene.
To determine the grams of compound C produced from 17.62 grams of compound A, we first need to calculate the number of moles of compound A. This is done by dividing the mass of compound A by its molar mass: ( \text{moles of A} = \frac{17.62 , \text{g}}{159.7 , \text{g/mole}} \approx 0.110 , \text{moles of A} ). If the reaction between compound A and compound B produces compound C in a 1:1 molar ratio, then 0.110 moles of A would yield 0.110 moles of C. Finally, converting moles of C to grams gives ( \text{grams of C} = 0.110 , \text{moles} \times 57.6 , \text{g/mole} \approx 6.35 , \text{g} ).
To determine the number of moles of THC in 26 μg, we first need to calculate the molar mass of THC which is approximately 314.47 g/mol. Then, we divide the given mass (26 μg or 0.000026 g) by the molar mass to find the moles. This gives us approximately 8.3 x 10^-8 moles of THC.
To find the number of moles of carbon (C), you need to divide the given mass by the molar mass of carbon. The molar mass of carbon is approximately 12.01 g/mol. Therefore, 0.170 g of carbon is equal to 0.170 g / 12.01 g/mol = 0.014 moles of carbon.
To convert grams of carbon to moles, divide the given mass by the molar mass of carbon. The molar mass of carbon is approximately 12 g/mol. Therefore, 28093g of carbon is equal to 28093g / 12g/mol ≈ 2341 moles of carbon.
Balanced chemical equation along with the stoichiometric ratios derived from that chemical reaction. A + B --> 2C mass of A * 1/molar mass of A = moles of A Moles of A * 2 moles of C/mole of A = moles of C Moles of C * molar mass of C = mass of C Also, you must think about limiting reagents, because if there is not enought reactant B to react with the amount of reactant A then the amount of reactant B will limit the production of product C!
To find the number of moles of carbon (C) in 32.6 g of ethane (C2H6), first calculate the molar mass of C2H6, which is approximately 30.07 g/mol. Since each molecule of C2H6 contains 2 moles of carbon, the total number of moles of C in 32.6 g of C2H6 can be found by dividing the mass by the molar mass and then multiplying by 2. This gives: [ \text{Moles of C} = \left(\frac{32.6 , \text{g}}{30.07 , \text{g/mol}}\right) \times 2 \approx 2.16 , \text{moles of C}. ]
To determine the number of moles of aluminum present in 856g, you need to divide the mass by the molar mass of aluminum. The molar mass of aluminum is approximately 26.98 g/mol. So, 856g ÷ 26.98 g/mol ≈ 31.7 moles of aluminum are present in 856g.
To calculate the number of moles of carbon (C) in 90g of CO2, you first need to determine the molar mass of CO2. Carbon has a molar mass of 12.01 g/mol, and CO2 has a molar mass of 44.01 g/mol (12.01 + 2*16.00). So, 90g of CO2 is equal to 90g / 44.01 g/mol = approximately 2.04 moles of CO2. Since each CO2 molecule contains 1 carbon atom, there are also 2.04 moles of carbon (C) in 90g of CO2.
When 4,000 grams of acetylene (C₂H₂) burns completely, it reacts with oxygen to produce carbon dioxide (CO₂) and water (H₂O). The balanced equation for the combustion of acetylene is: 2 C₂H₂ + 5 O₂ → 4 CO₂ + 2 H₂O. The molar mass of C₂H₂ is approximately 26 g/mol, so 4,000 g corresponds to about 153.85 moles of C₂H₂. From the equation, 2 moles of C₂H₂ produce 4 moles of CO₂, meaning 153.85 moles of C₂H₂ will produce 307.7 moles of CO₂. Therefore, the total mass of CO₂ produced is approximately 13,511 grams (or 13.5 kg).
Molar mass of ethanoic acid = (1x12) + (3x1) + (1x12) + (2x16) + (1x1) = 60 no. of moles = mass/ molar mass = 21.71/60 = 0.362 moles
By definition, one mole would be the same as the atomic mass. You take the number of moles and multiply it by the atomic mass. So if you have just 1 mole, the number of grams will be the atomic mass. Carbon's atomic mass is 12.011 grams.
To determine this we must first know what the molar mass of Carbon is and that equals 12.01g. This mean for every 12.01g of Carbon, we have one mole. Therefore:48gC x (1 mole C/ 12.01g C) = 3.99 molesRounded off, in 48g of Carbon there are about 4 moles.
Divide the Molar Mass of C and Cl4 by 56 to get your awnswer!