Divide mass (g) by molar mass (g/mol) :
30 g C2H2 = 30/26 g
35 g H2O = 35/18 g
To find the number of moles of carbon in 90g of carbon dioxide, you need to consider its molar mass. The molar mass of carbon dioxide is 44.01 g/mol. Calculate the moles of carbon using the molar mass, which will be approximately 2 moles.
The same. 0.233 moles C (1mol C/1mo CO2 ) = 0.233 moles of Carbon.
1 mole of CO2 has 1 mole of carbon atoms and 2 moles of oxygen atoms. So, 0.000831 mole of CO2 will have 0.000831 mole of carbon atoms.
1 mole of CO2 has 1 mole of carbon atoms and 2 moles of oxygen atoms. So, 167 mole of CO2 has 167 mole of carbon atoms.
In the balanced chemical equation for the formation of CO2 from C and O, the ratio of C to O is 1:2. Therefore, for 0.371 mole of C, you would need 0.742 moles of O to combine with it to form CO2.
To find the number of moles of carbon in 90g of carbon dioxide, you need to consider its molar mass. The molar mass of carbon dioxide is 44.01 g/mol. Calculate the moles of carbon using the molar mass, which will be approximately 2 moles.
The same. 0.233 moles C (1mol C/1mo CO2 ) = 0.233 moles of Carbon.
1 mole of CO2 has 1 mole of carbon atoms and 2 moles of oxygen atoms. So, 0.000831 mole of CO2 will have 0.000831 mole of carbon atoms.
1 mole of CO2 has 1 mole of carbon atoms and 2 moles of oxygen atoms. So, 167 mole of CO2 has 167 mole of carbon atoms.
This is a chemical calculation. 2.5 moles will C reacting with O2.
In the balanced chemical equation for the formation of CO2 from C and O, the ratio of C to O is 1:2. Therefore, for 0.371 mole of C, you would need 0.742 moles of O to combine with it to form CO2.
1 mole of CO2 has 1 mole of carbon atoms and 2 moles of oxygen atoms.
if you mean 10^22 O atoms, then this is how you do it: (8.16X10^22)/2=4.08X10^22 so there are 4.08X10^22 molecules, divided by 6.022X10^23(1 mole) is .06775, so there are that many moles of CO2. If you wanted to know how many moles of overall atoms there were, there's 4.08X10^22 molecules, 1 C in each so 4.08X10^22 C, and 8.16X10^22 O=1.224X10^23, and that's how many atoms, so that divided by 1 mole is (most accurate answer i can get you) .2032547326 moles of atoms so .2032547326 moles of atoms or .06775 moles of molecules/CO2
In 2.4 moles of CO2, there are 2.4 moles of carbon (C) atoms because each molecule of CO2 contains one carbon atom. To find the number of carbon atoms, you can multiply the number of moles by Avogadro's number (approximately (6.022 \times 10^{23}) atoms/mole). Therefore, the total number of carbon atoms is (2.4 \text{ moles} \times 6.022 \times 10^{23} \text{ atoms/mole} \approx 1.44 \times 10^{24} \text{ C atoms}).
The combustion of butane (C₄H₁₀) can be represented by the balanced equation: 2 C₄H₁₀ + 13 O₂ → 8 CO₂ + 10 H₂O. From this equation, we see that 2 moles of butane produce 8 moles of carbon dioxide. Therefore, if 5.31 moles of C₄H₁₀ are used, the moles of CO₂ produced can be calculated as follows: (5.31 moles C₄H₁₀) × (8 moles CO₂ / 2 moles C₄H₁₀) = 21.24 moles of CO₂.
13.3g C + O2 = CO2 m(C)=4g => n(C)=4/12=0,333mol m(O2)=10.67g => n(O2)=10.67/28=0,381mol we have excess of oxigen n(CO2)=n(C)=0,333 m(CO2)=0.333*40=13.3g
To calculate the number of moles in 2400g of CO2, we first need to determine the molar mass of CO2. The molar mass of CO2 is approximately 44.01 g/mol (12.01 g/mol for C + 2 x 16.00 g/mol for O). Then, we can use the formula: moles = mass / molar mass. Therefore, 2400g / 44.01 g/mol ≈ 54.5 moles of CO2.