This is a chemical calculation. 2.5 moles will C reacting with O2.
For this reaction, the stoichiometry indicates that 4 moles of CO2 are produced for every 2 moles of C2H2 reacted. The molar mass of CO2 is approximately 44 g/mol. Therefore, you can calculate the mass of CO2 produced by converting the moles of CO2 into grams.
5.0 grams CO2 (1mol CO2/44.01g) = 0.11 moles CO2
To calculate the moles of O2 produced, first find the moles of CO2 using its molar mass, which is 44.01 g/mol. Then, use the mole ratio from the balanced equation to find the moles of O2 produced. Finally, multiply the moles of CO2 by the mole ratio to get the moles of O2 produced.
Since acetylene (C2H2) has a stoichiometry of 2 moles of acetylene to produce 2 moles of CO2, three moles of acetylene would produce 3 moles of CO2. The reaction with excess oxygen ensures that all the acetylene is fully converted to CO2.
If carbon dioxide reacts with hydrogen to form water, the balanced chemical equation is: CO2 + 2H2 -> CH2O + 2H2O. It shows that 1 mole of CO2 produces 2 moles of H2O. Therefore, from 25 moles of CO2, 50 moles of H2O can be produced.
How many moles of CO2 are produced when 2.1 mol of C2H2 react?
For this reaction, the stoichiometry indicates that 4 moles of CO2 are produced for every 2 moles of C2H2 reacted. The molar mass of CO2 is approximately 44 g/mol. Therefore, you can calculate the mass of CO2 produced by converting the moles of CO2 into grams.
5.0 grams CO2 (1mol CO2/44.01g) = 0.11 moles CO2
To calculate the moles of O2 produced, first find the moles of CO2 using its molar mass, which is 44.01 g/mol. Then, use the mole ratio from the balanced equation to find the moles of O2 produced. Finally, multiply the moles of CO2 by the mole ratio to get the moles of O2 produced.
To calculate the grams of CO2 produced by burning 22 grams of C3H8, first determine the moles of C3H8 using its molar mass, then use the balanced chemical equation for the combustion of C3H8 to find the moles of CO2 produced, and finally convert moles of CO2 to grams using the molar mass of CO2.
Since acetylene (C2H2) has a stoichiometry of 2 moles of acetylene to produce 2 moles of CO2, three moles of acetylene would produce 3 moles of CO2. The reaction with excess oxygen ensures that all the acetylene is fully converted to CO2.
For every 2 moles of O2 produced, 3 moles of CO2 are used in the reaction. So you need to calculate the moles of O2 produced first using its molar mass, then use the mole ratio to find the moles of CO2 used. Finally, convert the moles of CO2 to grams using its molar mass.
If carbon dioxide reacts with hydrogen to form water, the balanced chemical equation is: CO2 + 2H2 -> CH2O + 2H2O. It shows that 1 mole of CO2 produces 2 moles of H2O. Therefore, from 25 moles of CO2, 50 moles of H2O can be produced.
To calculate the mass of CO2 produced from 128.00 g of O2, you need to use the balanced chemical equation for the reaction. The molar ratio between O2 and CO2 is 1:2, so if you have 128.00 g of O2, you can calculate the mass of CO2 produced by first converting grams of O2 to moles, then using the mole ratio to find the moles of CO2, and finally converting moles of CO2 to grams.
For every 1 mole of CH4 that reacts, 1 mole of CO2 is produced. Therefore, 4 moles of CH4 will produce 4 moles of CO2. To calculate the mass of CO2 produced, you would need to multiply the moles of CO2 by its molar mass (44 g/mole) to get the total mass produced.
CO2 + 4H2 --> CH4 + 2H2O0.500 moles CO2 (1 mole CH4/1 mole CO2) = 0.500 moles CH40.500 moles CO2 (2 moles H2O/1 mole CO2) = 1.00 moles H2O-------------------------------------------------------------------------------------add= 1.50 moles total product====================
The balanced chemical equation for the combustion of acetylene is: 2C2H2 + 5O2 → 4CO2 + 2H2O. This means 2 moles of C2H2 produce 4 moles of CO2. Therefore, 1.3 moles of C2H2 will produce 2.6 moles of CO2, which is equivalent to approximately 84.8 grams of CO2.