In the combustion of C7H16, 7 moles of O2 are required to form 8 moles of CO2. From the given 19.4g of CO2, 1 mole of CO2 is equivalent to 44g. Using stoichiometry, we can calculate that 25.23g of O2 are consumed during the combustion.
1 mole of C6H6 produces 6 moles of CO2 during combustion. Therefore, 0.4000 moles of CO2 would require (0.4000 moles CO2) / (6 moles C6H6 per mole CO2) = 0.0667 moles of C6H6 to be completely combusted.
Since acetylene (C2H2) has a stoichiometry of 2 moles of acetylene to produce 2 moles of CO2, three moles of acetylene would produce 3 moles of CO2. The reaction with excess oxygen ensures that all the acetylene is fully converted to CO2.
5.0 grams CO2 (1mol CO2/44.01g) = 0.11 moles CO2
Do you mean this reaction? C6H12O6 + 6O2 -> 6CO2 + 6H2O 6 moles oxygen required. --------------------------------
The balanced chemical equation for the reaction of lithium hydroxide with carbon dioxide is 2 LiOH + CO2 -> Li2CO3 + H2O. The mole ratio of LiOH to CO2 is 2:1, meaning that 40 moles of LiOH are required to react with 20 moles of CO2.
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In the combustion of C7H16, 7 moles of O2 are required to form 8 moles of CO2. From the given 19.4g of CO2, 1 mole of CO2 is equivalent to 44g. Using stoichiometry, we can calculate that 25.23g of O2 are consumed during the combustion.
1 mole of CO2 has 1 mole of carbon atoms and 2 moles of oxygen atoms. So, 0.000831 mole of CO2 will have 0.000831 mole of carbon atoms.
The balanced chemical equation for the combustion of methane is CH4 + 2O2 -> CO2 + 2H2O. This means that for every mole of CH4 that reacts, one mole of CO2 is produced. The molar mass of CO2 is about 44g/mol, so 22g CO2 is equivalent to 0.5 moles. Therefore, 0.5 moles of CH4 are required to produce 22g of CO2.
How many moles of CO2 are produced when 2.1 mol of C2H2 react?
44.0095
1 mole of C6H6 produces 6 moles of CO2 during combustion. Therefore, 0.4000 moles of CO2 would require (0.4000 moles CO2) / (6 moles C6H6 per mole CO2) = 0.0667 moles of C6H6 to be completely combusted.
Since acetylene (C2H2) has a stoichiometry of 2 moles of acetylene to produce 2 moles of CO2, three moles of acetylene would produce 3 moles of CO2. The reaction with excess oxygen ensures that all the acetylene is fully converted to CO2.
The same. 0.233 moles C (1mol C/1mo CO2 ) = 0.233 moles of Carbon.
5.0 grams CO2 (1mol CO2/44.01g) = 0.11 moles CO2
Do you mean this reaction? C6H12O6 + 6O2 -> 6CO2 + 6H2O 6 moles oxygen required. --------------------------------