CH4(g)+2CO2(g)->CO2(g)+2H2O(g)
44g CO2(g) is obtained from 16 g CH4(g)
mole of CO2 g
=22g CO2(g)*1mol CO2/44g CO2
=0.5 mol CO2 (g)
When methane undergoes complete combustion, the equation for the reaction is CH4 + 2 O2 -> CO2 + 2 H2O. This shows that the number of moles of carbon dioxide formed are the same as the number of moles of methane reacted, so that 14 moles of carbon dioxide will be formed from 14 moles of methane.
Methane (CH4) has four atoms of hydrogen per molecule. If there are 3 moles of methane, then there are 12 moles of hydrogen.
To find the number of moles of methane in 8.02 g, you need to divide the given mass by the molar mass of methane (16.04 g/mol). 8.02 g / 16.04 g/mol = 0.500 moles of methane
The complete combustion of methane proceeds according to the equation: CH4 + 2 O2 = CO2 + 2 H2O. Therefore, each mole of methane produces two moles of water and 4 moles of methane will produce eight moles of water.
For each mole of methane hydrate, there are 5.75 moles of water associated with it. In this case, since you have 160 cm³ of methane and 1000g of water, we first convert 160 cm³ of methane to moles, which is 5.62 moles. Then we calculate the moles of water based on the ratio 1:5.75 for methane to water in methane hydrate, which gives us approximately 32.3 moles of water associated with the 5.62 moles of methane.
800 g oxygen are needed.
Methane (CH4) has four atoms of hydrogen per molecule. If there are 3 moles of methane, then there are 12 moles of hydrogen.
When methane undergoes complete combustion, the equation for the reaction is CH4 + 2 O2 -> CO2 + 2 H2O. This shows that the number of moles of carbon dioxide formed are the same as the number of moles of methane reacted, so that 14 moles of carbon dioxide will be formed from 14 moles of methane.
To find the number of moles of methane in 8.02 g, you need to divide the given mass by the molar mass of methane (16.04 g/mol). 8.02 g / 16.04 g/mol = 0.500 moles of methane
0.25 moles
the required equation is HgCl2+4KI>>2KCl+K2HgI4. according to stoichiometric calculations 4 moles of KI gives 1 mole of k2HgI4 THEREFORE 0.4 moles of K2HgI4 requires----- ? 0.4 moles x 4 moles/1 mole=1.6 moles therefore 1.6 moles of KI is required to produce 0.4 moles of K2HgI4
The complete combustion of methane proceeds according to the equation: CH4 + 2 O2 = CO2 + 2 H2O. Therefore, each mole of methane produces two moles of water and 4 moles of methane will produce eight moles of water.
The balanced chemical equation for the formation of iron(III) oxide (Fe2O3) from iron (Fe) and oxygen (O2) is: 4 Fe + 3 O2 → 2 Fe2O3. From the equation, it can be seen that 3 moles of O2 are required to produce 2 moles of Fe2O3. Therefore, to produce 107.9 moles of Fe2O3, you would need (107.9 moles Fe2O3) × (3 moles O2 / 2 moles Fe2O3) = 161.85 moles of O2.
For each mole of methane hydrate, there are 5.75 moles of water associated with it. In this case, since you have 160 cm³ of methane and 1000g of water, we first convert 160 cm³ of methane to moles, which is 5.62 moles. Then we calculate the moles of water based on the ratio 1:5.75 for methane to water in methane hydrate, which gives us approximately 32.3 moles of water associated with the 5.62 moles of methane.
Three moles of nitrogen are required to produce 2 moles of ammonia according to the balanced chemical reaction for ammonia synthesis. Therefore, 27 moles of nitrogen are required to produce 18 moles of ammonia.
If you think to 4 moles of methane the number is 24,088563428.10e+23.
To determine the moles of carbon dioxide produced from the combustion of methane, we first need to balance the chemical equation for the combustion of methane: CH4 + 2O2 → CO2 + 2H2O. From the balanced equation, we see that 1 mole of methane produces 1 mole of carbon dioxide. The molar mass of methane (CH4) is 16.05 g/mol, and the molar mass of carbon dioxide (CO2) is 44.01 g/mol. Therefore, 100.0 grams of methane is equivalent to 100.0 g / 16.05 g/mol = 6.23 moles of methane, which would produce 6.23 moles of carbon dioxide.