the required equation is HgCl2+4KI>>2KCl+K2HgI4.
according to stoichiometric calculations 4 moles of KI gives 1 mole of k2HgI4
THEREFORE 0.4 moles of K2HgI4 requires----- ?
0.4 moles x 4 moles/1 mole=1.6 moles
therefore 1.6 moles of KI is required to produce 0.4 moles of K2HgI4
800 g oxygen are needed.
The balanced chemical equation for the formation of iron(III) oxide (Fe2O3) from iron (Fe) and oxygen (O2) is: 4 Fe + 3 O2 → 2 Fe2O3. From the equation, it can be seen that 3 moles of O2 are required to produce 2 moles of Fe2O3. Therefore, to produce 107.9 moles of Fe2O3, you would need (107.9 moles Fe2O3) × (3 moles O2 / 2 moles Fe2O3) = 161.85 moles of O2.
To find out how many moles of FeCr2O7 are required to produce 107 moles of Fe2O3, we first need to consider the balanced chemical reaction. The reaction can be represented as: [ 2 , \text{FeCr}_2\text{O}_7 \rightarrow 2 , \text{Fe}_2\text{O}_3 + 2 , \text{Cr}_2\text{O}_3 ] From the equation, 2 moles of FeCr2O7 produce 2 moles of Fe2O3, which means 1 mole of FeCr2O7 produces 1 mole of Fe2O3. Therefore, to produce 107 moles of Fe2O3, you would need 107 moles of FeCr2O7.
To produce potassium nitride (K₃N), the balanced chemical equation is 6 K + N₂ → 2 K₃N. This indicates that 6 moles of potassium are required to produce 2 moles of potassium nitride. Therefore, to produce 2.0 moles of K₃N, you would need 6 moles of potassium.
The answer is 97,66 moles.
800 g oxygen are needed.
Three moles of nitrogen are required to produce 2 moles of ammonia according to the balanced chemical reaction for ammonia synthesis. Therefore, 27 moles of nitrogen are required to produce 18 moles of ammonia.
This is not a common reaction at standard temperature and pressure.
N2 + 3H2 -> 2NH3 The stoichiometric equation (or balanced equation) for the formation of ammonia from this we can read off the mole ratio between hydrogen and ammonia; 3M H2 needed to produce 2M NH3 times each by 9 (so the ratio remains the same and 18M NH3 is formed) 27M H2 needed to produce 18M NH3
Six moles of HCl will be required: Each mole of chlorine contains two chlorine atoms, but each mole of HCl contains only one chlorine atom and the other reagent noted contains no chlorine atoms.
To produce 1 mole of chloroform, you need 3 moles of chlorine. So, to produce 1.5 moles of chloroform, you would need 4.5 moles of chlorine. Converting moles to grams by using the molar mass of chlorine (35.5 g/mol) gives you 160.5 grams of chlorine required.
The answer is 97,66 moles.
Do you mean this reaction? C6H12O6 + 6O2 -> 6CO2 + 6H2O 6 moles oxygen required. --------------------------------
Given the balanced equation Kr + 3F2 --> KrF6 In order to find how many moles of F2 are needed to produce 3.0 moles of KrF6, we must convert from moles to moles (mol --> mol conversion). 3.0 mol KrF6 * 3 molecules F2 = 9.0 mol F2 --------- 1 molecule F2
To determine the moles of LiF required, use the formula: moles = molarity (M) * volume (L). Given a 7 M solution with a volume of vol L, the moles of LiF needed would be 7 * vol.
3.2 moles of water (H2O)
2 moles of nitrogen monoxide (NO) are produced from 1 mole of oxygen (O2) according to the balanced chemical equation 2NO = N2 + O2. One mole of NO has a molar mass of 30 g, so 90 g of NO corresponds to 3 moles of NO. Therefore, 3 moles of O2 are required to produce 90 g of NO, which is equivalent to (3 moles) x (32 g/mol) = 96 g of O2.