44.0095
19
1 mole of CO2 has 1 mole of carbon atoms and 2 moles of oxygen atoms. So, 0.000831 mole of CO2 will have 0.000831 mole of carbon atoms.
How many moles of CO2 are produced when 2.1 mol of C2H2 react?
1 mole of C6H6 produces 6 moles of CO2 during combustion. Therefore, 0.4000 moles of CO2 would require (0.4000 moles CO2) / (6 moles C6H6 per mole CO2) = 0.0667 moles of C6H6 to be completely combusted.
Since acetylene (C2H2) has a stoichiometry of 2 moles of acetylene to produce 2 moles of CO2, three moles of acetylene would produce 3 moles of CO2. The reaction with excess oxygen ensures that all the acetylene is fully converted to CO2.
The same. 0.233 moles C (1mol C/1mo CO2 ) = 0.233 moles of Carbon.
5.0 grams CO2 (1mol CO2/44.01g) = 0.11 moles CO2
To find the number of moles of CO2 in 22g, you first need to calculate the molar mass of CO2 (44.01 g/mol). Then, divide the given mass (22g) by the molar mass to get the number of moles. Therefore, 22g of CO2 is equal to 0.50 moles.
1 mole of CO2 has 1 mole of carbon atoms and 2 moles of oxygen atoms. So, 167 mole of CO2 has 167 mole of carbon atoms.
To determine the moles of O2 required to generate 3 moles of CO2, we can refer to the balanced chemical equation for the combustion of carbon (C) or a hydrocarbon, which typically follows the form: C + O2 → CO2. In this reaction, one mole of O2 produces one mole of CO2. Therefore, to generate 3 moles of CO2, you would need 3 moles of O2.
The answer is 4,1 CO2 moles.
To determine the grams of CO2 produced from 2.5 moles of O2, we first need to consider the balanced chemical equation for the combustion of a hydrocarbon (e.g., methane): CH4 + 2O2 → CO2 + 2H2O. From this equation, 2 moles of O2 produce 1 mole of CO2. Therefore, 2.5 moles of O2 would produce 1.25 moles of CO2. Since the molar mass of CO2 is approximately 44 grams/mol, 1.25 moles of CO2 corresponds to 55 grams (1.25 moles × 44 g/mol).