5.0 grams CO2 (1mol CO2/44.01g) = 0.11 moles CO2
6 moles
Balanced equation first, 2C6H14 + 19O2 >> 12CO2 + 14H2O 84.4 moles hexane (12 moles CO2/2 moles C6H14) = 506.4 moles of CO2
4 moles
6.02 ten to the power of 23
CH4(g)+2CO2(g)->CO2(g)+2H2O(g) 44g CO2(g) is obtained from 16 g CH4(g) mole of CO2 g =22g CO2(g)*1mol CO2/44g CO2 =0.5 mol CO2 (g)
to get the answer just take number of moles you have and multiply it by the molecular mass of the compound which is 22g/mol in lithium oxide's case. 23mol x 22g/mol = 506 g of Li2O
19
4,54 L of CO2 have 0,204 moles.
CO2 + 4H2 --> CH4 + 2H2O0.500 moles CO2 (1 mole CH4/1 mole CO2) = 0.500 moles CH40.500 moles CO2 (2 moles H2O/1 mole CO2) = 1.00 moles H2O-------------------------------------------------------------------------------------add= 1.50 moles total product====================
How many moles of CO2 are produced when 2.1 mol of C2H2 react?
44.0095
5.0 grams CO2 (1mol CO2/44.01g) = 0.11 moles CO2
6 moles
220mg of CO2 x (1 g / 1000mg) x (1 mole of CO2 / 44 g ) = 0.005 moles
1 mole of CO2 has 1 mole of carbon atoms and 2 moles of oxygen atoms. So, 0.000831 mole of CO2 will have 0.000831 mole of carbon atoms.
Balanced equation first, 2C6H14 + 19O2 >> 12CO2 + 14H2O 84.4 moles hexane (12 moles CO2/2 moles C6H14) = 506.4 moles of CO2