(90 g CO2 / (12.0+2*16.0) g/mol CO2) = 2.05 mol CO2 = 2.05 mol C
2.05 mol C * 12.0 g/mol C = 24.5 g C
Divide mass (g) by molar mass (g/mol) : 30 g C2H2 = 30/26 g 35 g H2O = 35/18 g
How many moles of C are needed to react with 0.490 mole SO2?
The same. 0.233 moles C (1mol C/1mo CO2 ) = 0.233 moles of Carbon.
1,4 moles of CO are produced.
Use stoichiometry to convert grams of Carbon to moles of carbon and solve. 28093g C *(1mol C/12.011g C)= 2338.94mol C
Divide mass (g) by molar mass (g/mol) : 30 g C2H2 = 30/26 g 35 g H2O = 35/18 g
The answer is 2,17 moles carbon.
How many moles of C are needed to react with 0.490 mole SO2?
The same. 0.233 moles C (1mol C/1mo CO2 ) = 0.233 moles of Carbon.
1,4 moles of CO are produced.
Use stoichiometry to convert grams of Carbon to moles of carbon and solve. 28093g C *(1mol C/12.011g C)= 2338.94mol C
The reaction is:2 C + O2 = 2 COSo 2,1 moles are obtained.
1,4 moles carbon monoxide are produced.
4,37.10e-18 C atoms are equivalent to 7,25.10e-6 moles.
This is a chemical calculation. 2.5 moles will C reacting with O2.
The atomic mass of carbon, C is 12.0Amount of C = mass of sample/molar mass = 0.170/12.0 = 0.0142mol There are 0.0142 moles of carbon in a 0.170g pure sample.
Dimethyl sulfoxide is the chemical name for the molecular formula C2H6OS. It is comprised of carbon (C). hydrogen (H) and oxygen (O). Based on the molecular formula we know that for every one mole of C2H6OS there are 2 moles of C atoms. Therefore, using this ratio of 1 mole C2H6O : 2 moles C the answer to the problem is 8 moles C.