To calculate the amount of C2H2 produced from H2O, we need to consider the stoichiometry of the reaction. The balanced equation for the reaction is 2H2O -> 2H2 + O2 -> 2C2H2. From 80 grams of H2O, we can calculate the amount of C2H2 produced using stoichiometry.
CaC2(s) + 2H2O(l) --> C2H2(g) + Ca(OH)2(aq) Number of moles greater than 1 are prefixes of molecule formula's. Example: '2' in 2H2O(l)
The chemical equation for the reaction of acetylene (C2H2) with two molecules of Br2 (bromine) is: C2H2 + 2Br2 → C2H2Br4
C2H2 (acetylene) has the lowest boiling point among the molecules listed. This is because it is a small, nonpolar molecule with weak intermolecular forces, which results in low boiling point.
For this reaction, the stoichiometry indicates that 4 moles of CO2 are produced for every 2 moles of C2H2 reacted. The molar mass of CO2 is approximately 44 g/mol. Therefore, you can calculate the mass of CO2 produced by converting the moles of CO2 into grams.
2C2H2 + 5O2 ------------->2H2O + 4CO21 mole Of C2H2 = 26.04g, O2 = 32g, H2O = 44.01g, CO2 = 18.01g2moleC2H2 -------------> 4moleCO22x(26.04g) -------------> 4x(18.01g)52.08 g C2H2 ---------> 176.04 g CO230000g C2H2 ---------> ?? =176.04x30000g/52.08 =101405.53 gAnswer=101405.53 gram of CO2
How many moles of CO2 are produced when 2.1 mol of C2H2 react?
CaC2 + 2H2O ==> C2H2 + Ca(OH)2moles of C2H2 produced = moles of Ca(OH)2 produced (1:1 mole ratio is the stoichiometry)moles of Ca(OH)2 produced = 7 g x 1mol/74.1 g = 0.0945 molesmoles C2H2 = 0.0945 molesgrams C2H2 = 0.0945 moles x 26 g/mole = 2.46 grams = 2 grams to 1 sig fig
To calculate the amount of C2H2 produced from H2O, we need to consider the stoichiometry of the reaction. The balanced equation for the reaction is 2H2O -> 2H2 + O2 -> 2C2H2. From 80 grams of H2O, we can calculate the amount of C2H2 produced using stoichiometry.
The equation for the reaction is 2 C2H2 + 5 O2 -> 4 CO2 + 2 H2O. Therefore, the minimum mole ratio of O2 to C2H2 to permit complete reaction is 5/2. The actual ratio present, 7.40/2.40 or about 3.08, is greater than this minimum; therefore, all the available C2H2 will react. The reaction equation shows that the number of moles of H2O produced is the same as the number of moles of C2H2 reacted. Therefore, 2.40 moles of H2O are produced. The gram molecular mass of H2O is about 18.015; therefore the mass of water produced is 43.2 grams, to the justified number of significant digits.
Yes, acetylene gas (C2H2) is produced by the reaction of calcium carbide (CaC2) with water. The chemical reaction generates acetylene gas, calcium hydroxide, and some heat. This process is commonly used in industrial settings for welding and cutting applications.
2C2H2 + 5O2 ---->4CO2 + 2H2O so 1 mole of acetylene (ethyne) reacts with 2.5 moles of oxygen. Answer 2.5 moles
The balanced chemical equation for the combustion of acetylene is: 2C2H2 + 5O2 → 4CO2 + 2H2O. This means 2 moles of C2H2 produce 4 moles of CO2. Therefore, 1.3 moles of C2H2 will produce 2.6 moles of CO2, which is equivalent to approximately 84.8 grams of CO2.
C2H2 (acetylene) is a linear molecule.
yep!! C2H2 is a pure subsatnce
The electron pair geometry of C2H2 is linear.
CaC2(s) + 2H2O(l) --> C2H2(g) + Ca(OH)2(aq) Number of moles greater than 1 are prefixes of molecule formula's. Example: '2' in 2H2O(l)