Copper (I) bromide
The chemical formula for the compound between copper and bromine is CuBr₂.
Two compounds are known: - copper(I) bromide: CuBr - copper (II) bromide: CuBr2
To find the weight of 500 moles of CuBr, you first need to determine the molar mass of CuBr which is 159.43 g/mol. Then, you can calculate the weight by multiplying the number of moles by the molar mass: 500 moles * 159.43 g/mol = 79,715 g.
Cu donates electrons to Br to form CuBr. It is a crystalline compound. The bonds have mixed ionic and covalent characters.
Cuprous bromide is CuBr (Copper(I) bromide) Compare to Cupric Bromide which is CuBr2 . (Copper(II) bromide).
Cu+2 Br-1
Copper (I) bromide. Unlike with a zinc compound question I just answered, the (I) here is pretty important; both copper (I) bromide and copper (II) bromide exist and are commercially available.
The chemical formula of copper(I) bromide is CuBr.
The chemical formula for copper(I) bromide is CuBr. It is a compound that contains one copper ion with a +1 charge and one bromide ion with a -1 charge.
Weight of one mole of CuBr=molecular weight of CuBr=(63.545+79.904)=143.449 g. So, weight of 0.500 mole of CuBr=(143.449 X 0.500)g=71.725 g.
Copper(I) bromide is CuBr. Copper(II) bromide is CuBr2