Cu donates electrons to Br to form CuBr. It is a crystalline compound. The bonds have mixed ionic and covalent characters.
K and Br would bond ionically, with potassium (K) donating an electron to bromine (Br) to form K+ and Br- ions, which are attracted to each other due to their opposite charges. This electrostatic attraction is what holds the two ions together in an ionic bond.
It is a molecule, atoms are only of one type and though both have partial charges due to the way the bond is formed they are not ions in this state.
Ba+2 Br-1 -----> these are the ions and their chargesBa+2 Br+1 Br+1 ----> the charges must add to zero, so one positive Br ion is added to cancel out the +2 Ba ionBaBr2 ------> simplifyName: Barium bromide
To find the weight of 500 moles of CuBr, you first need to determine the molar mass of CuBr which is 159.43 g/mol. Then, you can calculate the weight by multiplying the number of moles by the molar mass: 500 moles * 159.43 g/mol = 79,715 g.
Iron (Fe) is a metal that can be oxidized by two common ions: copper ions (Cu^2+) and silver ions (Ag^+).
Cu+2 Br-1
Two elements in copper bromide (misspelled, not bromiNe)There is Cu (cuprum) and Br(bromium) in it.
Cuprous bromide is CuBr (Copper(I) bromide) Compare to Cupric Bromide which is CuBr2 . (Copper(II) bromide).
The solution is unsaturated.
The formula for copper bromine is CuBr. Copper bromine is an ionic compound composed of copper cations (Cu+) and bromine anions (Br-).
The chemical formula for copper bromide containing the Cu+ ion is CuBr. This compound consists of a copper cation with a +1 charge (Cu+) and a bromide anion with a -1 charge (Br-), thus requiring one atom of each element to balance the charges.
The percent composition for CuBr2 is: Cu= 28.45% Br= 71.55%
The product of the ion concentrations is (in mol/L) [Cu+] * [Br-] = [4.5*10-5] * [3.4*10-5] = 1.53*10-9 This is LOWER than its solubility product Ksp 5.3*10-9, so the solution is UNDERsaturated.
CuF2 is an ionic compound because copper (Cu) is a metal and fluorine (F) is a nonmetal. Metal atoms tend to lose electrons, while nonmetal atoms tend to gain electrons to form ionic bonds. In CuF2, copper loses two electrons to fluorine atoms to form the compound.
copper has 29 protons, when dealing with Cu^2+ all that means is it lost two electrons. so now the element has 29 protons and 27 electrons. Protons are positive and electrons are negative and neutrons are neutral. So say you had an element X^2- then you have gained two more electrons so the element has an overall negative charge. hope that helps
In a neutral compound, the ratio of Sr2+ ions to Br- ions would be 1:2 to ensure overall charge neutrality. This means there would be one Sr2+ ion for every two Br- ions in the compound.
Copper (I) bromide. Unlike with a zinc compound question I just answered, the (I) here is pretty important; both copper (I) bromide and copper (II) bromide exist and are commercially available.