The genotype of a male solid black rabbit is likely to be either homozygous (BB) or heterozygous (Bb) for the black coat color gene, where "B" represents the dominant allele for black fur and "b" represents the recessive allele for other colors. If the rabbit is homozygous (BB), it carries two copies of the black allele. If it is heterozygous (Bb), it still exhibits the black coat color due to the dominance of the "B" allele.
Black coat homozygous: BB Black Coat heterozgous: Bb
50% of the rabbits will be cc and 50% of the rabbits will be Cc. The punnet square is simple because one rabbit is homozygous recessive and the other is heterozygous. The genotype is then defined by the heterozygous (Cc) rabbit.
A spotted rabbit has the genes Enen and a solid rabbit is enen. A cross between the two would have a 50% chance of being spotted ( called "broken" in the rabbit world) and 50% chance of being solid colored.
To determine the genotype of a rabbit, you would need to perform a genetic test, such as DNA sequencing or a genetic panel that assesses specific genetic markers. This information can help you understand the rabbit's genetic makeup and identify any inherited traits or predispositions. Consulting with a veterinarian or a specialized genetic testing service can provide more detailed insights into the rabbit's genotype.
One way to determine the male's genotype would be to breed him to females with a known genotype of Black-Black. If any resultant calves were born with a white coat, you would then know that the male were Black-White. If calves were consistently black coated, you could be fairly certain he was also of the Black-Black genotype.
Genotype codes for phenotype. Phenotype is the expressed trait, for example, black fur. The genome that codes for black fur would be BB for example
Usually if it's a white rabbit, it would have a red eye, but if it was a brown one or black one, then the color would be black or darkish brown
If the allele for solid is: ee The allele for spotted is:Ee An the Allele for charlie (very lightly spotted) is: EE Than with a solid and a spotted you will get: 50% spotted and 50% solid Two spotteds get:25% charlie 50% spotted and 25% solid Charlie and Solid get: 100% broken charlie and charlie get: 100% charlie solid and solid get 100% solid Over all charlie is most dominant, but spotted is dominant to solid
if a man were non- hemophiliac and he marries a woman whois homozygus for nan-hemophilia,give the possible genotypes of the children
No. They might have the same phenotype, but would not have the same genotype.
The probable phenotype of the offspring would be black, as black color is dominant over chestnut color. The genotype of the offspring would be heterozygous for black (Bb), since one parent is homozygous black (BB) and the other is homozygous chestnut (bb).
The mouse with the genotype BB would have black hair because the dominant allele B controls for black hair color.