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There are 90 palindromes with 4 digits.

The first digit can be any digit from the set {1,2,3,4,5,6,7,8,9}.

With each choice of the first digit, the second can be any digit from the set {0,1,2,3,4,5,6,7,8,9}.

That makes 9*10 = 90 permutations for the first two digits. These determine the palindrome since the third and fourth digits are the same as the second and first, respectively.


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10y ago

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