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A 9-digit palindrome has the structure where the first five digits determine the last four digits in reverse order. The first digit must be from 1 to 9 (to ensure it's a 9-digit number), giving us 9 options. The next four digits (the second to fifth digits) can each be any digit from 0 to 9, providing 10 options each. Therefore, the total number of 9-digit palindromes is (9 \times 10^4 = 90,000).
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How many 2 digit palindromes are possible?
9 of them.
How many palindromes are from 0 to 1000?
There are 199 palindromic numbers between 0 and 1000. These include single-digit numbers (0 to 9), two-digit numbers (e.g., 11, 22, ... 99), and three-digit numbers (e.g., 101, 111, ... 999). Each of these categories contributes to the total, with the three-digit palindromes being in the form of ABA, where A and B are digits.
How many palindromes between 900 and 1900?
Between 900 and 1900, the palindromes are numbers that read the same forwards and backwards. These are specifically the three-digit numbers in the form of "aba," where "a" is a digit from 9 to 1, and "b" is any digit from 0 to 9. The palindromes in this range are: 909, 919, 929, 939, 949, 959, 969, 979, 989, 999, 1001, 1111, 1221, 1331, 1441, 1551, 1661, 1771, 1881, and 1991. In total, there are 19 palindromes between 900 and 1900.
How many 4 digit palindromes are multiples of 9?
Nine. The sum of the digits must be a multiple of 9; because of the repeated digits, this is only possible if the first two digits add up to 9.
How many palindromes are there between 100 1000?
-900
How many palindromes are there between 900 - 1900?
-1000
How many 2 digit palindromes are possible?
9 of them.
How many 5-digit palindromes are multiples of 9?
-4
How many palindromes are from 0 to 1000?
There are 199 palindromic numbers between 0 and 1000. These include single-digit numbers (0 to 9), two-digit numbers (e.g., 11, 22, ... 99), and three-digit numbers (e.g., 101, 111, ... 999). Each of these categories contributes to the total, with the three-digit palindromes being in the form of ABA, where A and B are digits.
How many palindromes between 900 and 1900?
Between 900 and 1900, the palindromes are numbers that read the same forwards and backwards. These are specifically the three-digit numbers in the form of "aba," where "a" is a digit from 9 to 1, and "b" is any digit from 0 to 9. The palindromes in this range are: 909, 919, 929, 939, 949, 959, 969, 979, 989, 999, 1001, 1111, 1221, 1331, 1441, 1551, 1661, 1771, 1881, and 1991. In total, there are 19 palindromes between 900 and 1900.
How many 4 digit palindromes are multiples of 9?
Nine. The sum of the digits must be a multiple of 9; because of the repeated digits, this is only possible if the first two digits add up to 9.
How many palindromes are there between 100 1000?
-900
How many 4 digit numbers are palindromes?
There are 90 palindromes with 4 digits.The first digit can be any digit from the set {1,2,3,4,5,6,7,8,9}.With each choice of the first digit, the second can be any digit from the set {0,1,2,3,4,5,6,7,8,9}.That makes 9*10 = 90 permutations for the first two digits. These determine the palindrome since the third and fourth digits are the same as the second and first, respectively.
Are there more 11 digit or 12 digit palindromic numbers?
There are more 12-digit palindromic numbers than 11-digit palindromic numbers. This is because the number of possible 12-digit palindromic numbers is greater than the number of possible 11-digit palindromic numbers. In general, the number of palindromic numbers of length n is 9 * 10^((n-1)/2), so for 11-digit palindromic numbers, there are 9 * 10^5 = 900,000 possibilities, while for 12-digit palindromic numbers, there are 9 * 10^6 = 9,000,000 possibilities.
How many palindromes are there between 10000-99999?
There are 9,000 palindromes between 10,000 and 99,999. A five-digit palindrome takes the form (abcba), where (a) can range from 1 to 9 (9 options), and (b) and (c) can each range from 0 to 9 (10 options each). Thus, the total number of five-digit palindromes is (9 \times 10 \times 10 = 9000).
Can 100 different digits make 10010010000 different three digits palindromes why?
No, 100 different digits cannot make 10,010,010,000 different three-digit palindromes. A three-digit palindrome has the form "ABA," where A is the first and last digit, and B is the middle digit. Since A can be any digit from 1 to 9 (for the first digit) and B can be any digit from 0 to 9, there are only 9 options for A and 10 options for B, resulting in a total of 90 unique three-digit palindromes (9 x 10 = 90).
Is a single digit a palindrome?
Yes, a single digit is considered a palindrome because it reads the same forwards and backwards. For example, the digit "5" is the same in both directions. All single-digit numbers (0-9) are palindromes by this definition.
