Yes it is polar so it dissolves in water
Glucose is the solute; water is the solvent.
solvent
The total mass of the solution is the sum of the mass of the solute (glucose) and the mass of the solvent (water), which is 50 g + 1000 g = 1050 g. The mass percent of the solute (glucose) in the solution is the mass of the solute divided by the total mass of the solution, multiplied by 100. Therefore, the mass percent of glucose in the solution is (50 g / 1050 g) x 100 = 4.76%.
Glucose
Yes, during process of osmoses the solvent from higher concentration to lower concentration moves through semipermeable membrane, the 2% solution has lower concentration of solute therefore higher concentration of solvent.
No. For the physical formula ratio, of [solute:solvent] to be the same, you would have to use twice as much glucose as sucrose, to make the solution; because sucrose is a disaccharide. But, when preparing the solution, the actual weight used will be approximately the same. You have a solution, with solute sucrose, at 1C ratio. Weighing the same amount of glucose (in grams), will make a solution of 2C ratio. General expression is Glucose:Sucrose::2:1.
No, glucose is a substance, osmosis is a process. Glucose is a simple sugar and is made by photosynthesis in plant cells. Osmosis is the flow of water through a semi-permeable membrane from a region where there is a higher concentration of water to where there is a lower concentration of water. Osmosis happens in plant cells because the cell membrane is semi-permeable. The direction of water flow depends on how much glucose is dissolved in the cell sap compared to how much is in the liquid surrounding the cells. Thus glucose is involved in the process of photosynthesis.
The vapor pressure of a 10% glucose solution will be lower than that of pure water because the presence of the solute (glucose) lowers the vapor pressure of the solution compared to the pure solvent (water). The exact vapor pressure will depend on the concentration of the solution and the nature of the solute.
The solution is 0,25 M.
The transport involved is osmosis, where water molecules move across a semipermeable membrane from an area of lower solute concentration to an area of higher solute concentration, in this case, into the more concentrated glucose solution.
The molarity of a solution with 3 mol of glucose in 6 kg of water cannot be determined without knowing the volume of the solution. Molarity is defined as the amount of solute (in mol) divided by the volume of the solution in liters. Without the volume, the molarity of the solution cannot be calculated.
The answer is of course 6 moles.