Glucose is the solute; water is the solvent.
A 30% glucose solution is purely glucose and water, though it is actually impossible to keep other contaminants out of it. To create a 30% solution of glucose, you take a fixed volume of water and add 30% of that value of glucose to the water. The amount of glucose is in grammes. For example, 3g of glucose would be added to 10ml of water.
In the solution you are preparing by mixing 10 grams of glucose into distilled water, the solvent is distilled water, while the solute is glucose. The solvent is the substance that dissolves the solute, and in this case, water acts as the medium in which glucose is dissolved. Thus, glucose is the solute that gets dispersed in the solvent, forming a homogeneous solution.
To determine the mass of the solution, we need to calculate the total mass of the solution when 81g of glucose is added. Since the solution is 15.0% glucose by mass, the remaining 85.0% is water. Therefore, the total mass of the solution can be calculated using the mass of glucose added and the percentage of water. This would result in a total mass of solution greater than 81g due to the addition of water to dissolve the glucose.
To find the percent by mass of the solution, first calculate the total mass of the solution, which is the sum of the mass of glucose and the mass of water: 50.0 g (glucose) + 1000.0 g (water) = 1050.0 g. The percent by mass of glucose in the solution is then calculated as (mass of glucose / total mass of solution) × 100 = (50.0 g / 1050.0 g) × 100 ≈ 4.76%. Therefore, the percent by mass of glucose in the solution is approximately 4.76%.
To prepare a 50mm glucose solution, you would need to dissolve 9g of glucose in enough water to make 100mL of solution. This would give you a solution with a concentration of 50mm (millimolar).
A 30% glucose solution is purely glucose and water, though it is actually impossible to keep other contaminants out of it. To create a 30% solution of glucose, you take a fixed volume of water and add 30% of that value of glucose to the water. The amount of glucose is in grammes. For example, 3g of glucose would be added to 10ml of water.
Isotonic solution is very close to sea water in composition and also concentration. Glucose isotonic solution is an electrolyte solution used for re-hydration. It contains salt, water and glucose.
No, glucose itself does not contain electrolytes. Electrolytes are typically ions such as sodium, potassium, chloride, and bicarbonate that can conduct electricity in solution. If electrolytes are needed, they would have to be added separately to a glucose solution.
Glucose solution is a homogeneous mixture because it is composed of glucose dissolved in water, making it uniform throughout.
To prepare a 10% glucose solution, you would mix 10 grams of glucose with enough water to make a total solution volume of 100 ml. This means the final solution would contain 10 grams of glucose and 90 ml of water.
In the solution you are preparing by mixing 10 grams of glucose into distilled water, the solvent is distilled water, while the solute is glucose. The solvent is the substance that dissolves the solute, and in this case, water acts as the medium in which glucose is dissolved. Thus, glucose is the solute that gets dispersed in the solvent, forming a homogeneous solution.
To determine the mass of the solution, we need to calculate the total mass of the solution when 81g of glucose is added. Since the solution is 15.0% glucose by mass, the remaining 85.0% is water. Therefore, the total mass of the solution can be calculated using the mass of glucose added and the percentage of water. This would result in a total mass of solution greater than 81g due to the addition of water to dissolve the glucose.
Dissolve 10 g pure glucose in 100 mL distilled water.
To find the molality of a solution, you need the mass of the solvent (usually water) in kilograms and the number of moles of solute (glucose). Given that the solution is 7.80% glucose by weight, you can calculate the mass of glucose in the solution and then convert it to moles using the molar mass of glucose. From there, you can find the molality by dividing the moles of glucose by the mass of the solvent in kilograms.
The balloon will contain a mixture of the 10% and 5% glucose solutions. Since water can pass through but not glucose, the glucose concentration inside the balloon will decrease over time as water moves from the lower concentration in the beaker to the higher concentration in the balloon through osmosis.
Glucose is a simple sugar or monosacharide. It may be presented as a white powerder or solid, or in solution with sterile water.
To find the percent by mass of the solution, first calculate the total mass of the solution, which is the sum of the mass of glucose and the mass of water: 50.0 g (glucose) + 1000.0 g (water) = 1050.0 g. The percent by mass of glucose in the solution is then calculated as (mass of glucose / total mass of solution) × 100 = (50.0 g / 1050.0 g) × 100 ≈ 4.76%. Therefore, the percent by mass of glucose in the solution is approximately 4.76%.