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Perhaps you meant speed or velocity, because the vertical acceleration is constant throughout the bomb's decent, ignoring the effects of air resistance. The acceleration due to gravity is 9.8 m/s2 for all values of t.

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What is the acceleration of a freely falling object 2 seconds after it has been released from height of M?

The acceleration of a freely falling object is approximately 9.81 m/s^2, directed downwards towards the center of the Earth. Therefore, the acceleration of the object 2 seconds after being released will still be 9.81 m/s^2, assuming no other forces are acting on it.


Does height affect acceleration?

the gravitational pull makes the object fall quicker. it doesn't matter about weith


What is the height of a ball dropped from 80 meters after 3 seconds?

The height of the ball after 3 seconds can be calculated using the formula for free fall: ( h = h_0 - \frac{1}{2} g t^2 ), where ( h_0 ) is the initial height (80 meters), ( g ) is the acceleration due to gravity (approximately 9.81 m/s²), and ( t ) is the time in seconds. After 3 seconds, the height is ( h = 80 - \frac{1}{2} \times 9.81 \times (3^2) ), which simplifies to ( h = 80 - 44.145 ). Therefore, the height of the ball after 3 seconds is approximately 35.855 meters.


How far will a rubber ball fall in ten seconds?

The distance a rubber ball falls in 10 seconds will depend on the height from which it is dropped and the acceleration due to gravity. On Earth, neglecting air resistance, the general equation to calculate the distance fallen is: distance = 0.5 * acceleration due to gravity * time^2.


David drops a ball from a bridge at an initial height of 70 meters what is the height of the ball to the nearest tenth of a meter exactly 2 seconds after he releases the ball?

Distance of fall in T seconds = 1/2 g T2Distance of fall in 2 seconds = (1/2) (9.8) (2)2 = (4.9 x 4) = 19.6 metersHeight of this particular ball after 2 seconds = (70 - 19.6) = 50.4 meters


How long will an object be in the air if it falls from a height of 5.9 meters?

distance (s) = 1/2 acceleration (a) x time (t) squared or s = 1/2 at^2.; a = gravity acceleration = 9.81m/s/s so time is 1.1 seconds


A rock falls off a bridge and hits the water 8 seconds later How high is the bridge?

The height of the bridge can be calculated using the formula: distance = 0.5 * acceleration due to gravity * time^2. Given that the rock takes 8 seconds to hit the water, the height of the bridge would be approximately 313.6 meters.


Can acceleration due to gravity vary with respect to height?

No, acceleration due to gravity is a constant at 9.81ms-2. It cannot be influenced by other factors such as height.


How do I work out a vertical height when it gives me kg and kJ of Ep and Gravity?

Ep (joules) = mass * acceleration due to gravity * height So: height = Ep / (mass * acceleration due to gravity)


How does height affect acceleration?

Height does not directly affect acceleration. Acceleration is determined by the force applied to an object, its mass, and any friction or air resistance. However, height can influence potential energy, which can be converted into kinetic energy and affect the speed of an object as it moves downhill.


What is A ball is dropped from 5 m height What is its acceleration when it is at a height of 2.5 m?

Its acceleration is always the same - the acceleration of gravity at 32 ft/sec/sec - no matter what distance it is during drop, until it hits the ground.


What is the acceleration of the object in m/s/s when it is dropped from a height of 10 meters?

The acceleration of an object dropped from a height of 10 meters is approximately 9.81 m/s2.