x = 6.5y = 16.9
No, the diagonals of a parallelogram are not normally congruent unless the parallelogram is a rectangle.
Yes. The diagonals of any parallelogram bisect each other. A rectangle is a special case of a parallelogram.
This cannot be proven, because it is not generally true. If the diagonals of a quadrilateral bisect each other, then it is a parallelogram. And conversely, the diagonals of any parallelogram bisect each other. However not every parallelogram is a rhombus.However, if the diagonals are perpendicular bisectors, then we have a rhombus.Consider quadrilateral ABCD, with diagonals intersecting at X, whereAC and BD are perpendicular;AX=XC;BX=XD.Then angles AXB, BXC, CXD, DXA are all right angles and are congruent.By the ASA theorem, triangles AXB, BXC, CXD and DXA are all congruent.This means that AB=BC=CD=DA.Since the sides of the quadrilateral ABCD are congruent, it is a rhombus.
Yes the diagonals of a parallelogram have the same midpoint since they bisect each other.
False
No. If the diagonals of a parallelogram are congruent then it must be a rectangle (or square).
True
No.
False. Bisecting diagonals is sufficient to guarantee a parallelogram, but the diagonals will only be perpendicular if the sides of the parallelogram are equal.
True
diagonals.
A parallelogram is one of them.
A parallelogram
true
The missing word is "bisect".
always
false